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SpyIntel [72]
3 years ago
6

How do I solve for c and d

Mathematics
1 answer:
tankabanditka [31]3 years ago
6 0
For c using proportionality of corresponding sides you can writing 

(3c+4)       9
--------- = -------
    20         15

(3c+4)       3
---------- = ------    cross multiple 
    20          5

5(3c+4) = 20*3   divide both sides by 5

3c+4=4*3

3c+4=12

3c = 8

c = 8/3

for d you can writing 

(2d-3)       9
--------- = ------
   12          15

(2d-3)       3
--------- = -------   cross multiple 
   12          5

5(2d-3) = 12*3

10d -15 = 36

10d = 51

d = 51/10

d = 5,1

hope helped 

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A+b=77,a-b=13 care sun nr
STALIN [3.7K]
It's a simultaneous equation:
Steps:
1.Number the equations..

a+b=77 -1
a-b=13 -2

2. Choose what variable you want to use. In this case I would use the "b". Since the signs in front of the "b's" are different, add the two equations together

a + b = 77
+ + +
a (-b) = 13

Which gives;
2a = 90

Then solve to find a:
2a=90
a= 90/2
a=45

3.Then plug the "a" value into any of the original equations to find the "b" value. I would use equation 1 since the all the variables are positive.

a + b = 77
(45) + b = 77
b=77-45
b=32

4.Solution

a=45
b=32
3 0
3 years ago
A. 18 is 20 percent of what number? B. 15 is 25 percent of what number? C. 12 is 30 percent of what number? D. 24 is 40 percent
3241004551 [841]

Answer:

18=x*.20

15=x*.25

12=x*.30

24=x*.40

39=x*.60

78=x*.30

Step-by-step explanation:

To solve for x on each, divide the number on the left of the equal side by the number x is being multiplied by.  For example, 18/.20=x

5 0
3 years ago
Read 2 more answers
SOMEONE PLZZ HELP, I HAVE A TEST AND DONT KNOW HOW TO DO THIS!!
Harman [31]
I believe it is C.
Good luck!
5 0
2 years ago
A bag of skittles candy was found to have 15% of the candies to be red, 15% were orange, 10% yellow and 20% green. The rest were
harkovskaia [24]

It is a very low probability because forty percent is purple

8 0
2 years ago
The sum of two confescutive integers is at least 46. What is the least possibly pair of integers?
dezoksy [38]
An integer is a whole number. Sum means to add and since they are consecutive, there is only a difference of 1 between them.

1) 21 + 23: not consecutive
2) 23+24= 47: has to be at least 46
3) 22+23= 45: has to be at least 46
4) 24+25= 49: has to be at least 46

So we have two possibilities: either #2 or #4. Find least possible pair of integers.

x= first integer
x+1= second integer

x + (x+1) >= 46
2x + 1 >=46
2x>=45
x>=22.5

Answer:
The first integer has to be greater than or equal to 22.5. Since integers are whole numbers, round up to the next whole number. The least possible integers are #2) 23 and 24.

Hope this helps! :)
3 0
3 years ago
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