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SpyIntel [72]
2 years ago
6

How do I solve for c and d

Mathematics
1 answer:
tankabanditka [31]2 years ago
6 0
For c using proportionality of corresponding sides you can writing 

(3c+4)       9
--------- = -------
    20         15

(3c+4)       3
---------- = ------    cross multiple 
    20          5

5(3c+4) = 20*3   divide both sides by 5

3c+4=4*3

3c+4=12

3c = 8

c = 8/3

for d you can writing 

(2d-3)       9
--------- = ------
   12          15

(2d-3)       3
--------- = -------   cross multiple 
   12          5

5(2d-3) = 12*3

10d -15 = 36

10d = 51

d = 51/10

d = 5,1

hope helped 

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A circle has a diameter of 12 inches. What is the area of the circle? А 367 inches squared B 247 inches squared C 127 inches squ
Ann [662]

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113.1

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Nia is three years older than half Jordans age , if Jordan is eight years old , how old is Nia?
Kobotan [32]
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8 0
3 years ago
9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent
Veseljchak [2.6K]

Answer:

63.5

Step-by-step explanation:

The diagonals of a rhombus bisect opposite angles.

The longer diagonal bisects the 42° angle

The larger angle of the rhombus is 180 - 42 = 138

Let x = the length of the longer diagonal

You know two sides and the included angle of a triangle.

Using the law of cosines we get

x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.150837...\\x = \sqrt{4030.150837} = 63.48x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.1508...\\     x = \sqrt{4030.1508} \\          =  63.48x^2 = 34^2 + 34^2 - 2(34)(34) cos 138

      = 1156 + 1156 - 2312 c0s 138

      = 4030.1508...

x = sq rt 4030.1508...

  =  63.5

7 0
2 years ago
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