How do I solve for c and d
1 answer:
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<em>Note:</em>
<em>Your first question is missing the y-intercept, so I am solving the 2nd question. You would still get your concept clear because the procedure to solve each of the questions is the same.</em>
Question 2
Answer:
The equation in the standard form is:
- 2/3x + y = -4
Please also check the attached graph.
Step-by-step explanation:
We know that the equation in the standard form is
Ax + By = C
where x and y are variables and A, B and C are constants
Given
- Slope m = -2/3
- y-intercept = -4
To determine
- Write the equation in the standard form
We know that the slope-intercept form of the line equation
where
- m is the slope
- b is the y-intercept
In our case:
- Slope m = -2/3
- y-intercept = -4
substituting m = -2/3 and y-intercept b = -4 in the slope-intercept of the line equation
y = mx+b
y = -2/3x + (-4)
y = -2/3x - 4
Writing the equation in the standard form
2/3x + y = -4
Therefore, the equation in the standard form is:
- 2/3x + y = -4
Please also check the attached graph.
Area of a triangle:
A= (1/2)(bh)
In this problem we are given:
A= 178.5
b= h+4 in
h= UNKNOWN ("h")
Plug in our values into the area equation and solve for "h":
(multiply each side by 2 to get rid of the 1/2)
(357/21=17)
(solve both inequalities separately)
( a negative height is not possible so, this answer is incorrect.)
Answer: base = (h+4)= (17+ 4) b= 21 in h= 17in
Please comment with any further questions! :)
A= (1/2)(bh)
In this problem we are given:
A= 178.5
b= h+4 in
h= UNKNOWN ("h")
Plug in our values into the area equation and solve for "h":
(357/21=17)
Answer: base = (h+4)= (17+ 4) b= 21 in h= 17in
Please comment with any further questions! :)