D. they require more testing in real-word conditions
An object with high mass accelerating quickly. Assuming the objects have the same volume, the third choice will be the most dense, and therefore will take a longer time and a stronger opposite force to slow it down to a complete stop due to its high acceleration rate, as well.
Pretty good for a 13 year old, huh? :D
Answer:
The drill's angular displacement during that time interval is 24.17 rad.
Explanation:
Given;
initial angular velocity of the electric drill, = 5.21 rad/s
angular acceleration of the electric drill, α = 0.311 rad/s²
time of motion of the electric drill, t = 4.13 s
The angular displacement of the electric drill at the given time interval is calculated as;
Therefore, the drill's angular displacement during that time interval is 24.17 rad.
Answer:
Explanation:
Gauss' Law should be applied to find the E-field 3.9 cm from the surface of the sphere.
In order to apply Gauss' Law, an imaginary spherical shell (Gaussian surface) should be placed around the original sphere. The exact position of the shell must be 3.9 cm from the surface of the original sphere.
Gauss' Law states that
Here, the integral in the left-hand side is equal to the area of the imaginary surface. After all, the reason behind choosing the imaginary surface a spherical shell is to avoid this integral. The enclosed charge in the right-hand side is equal to the charge of the sphere, -84.0 nC. The radius of the imaginary surface must be 5 + 3.9 = 8.9 cm.
So,
Answer:
force pushed the object = 10 × 5 = 50N