The uniform diving board has a mass of 35 kg . A B 0.8 m 4 m Find the force on the support A when a 65 kg diver stands at the en
d of the diving board. The acceleration of gravity is 9.81 m/s 2 . Answer in units of kN.
1 answer:
Answer:
In other to get the force at the support A, we apply the principle of forces in equilibrium
For a system of forces to be at equilibrium, the sum of all upward forces must be equal to the sum of all downward forces
what are the forces in this system;
for exerted by diver = 65X9.81 = 637.65N = 0.64kN (acting downward)
weight of diving board = 35X9.81 = 343.35N = 0.3434kN (acting downward)
the reaction at point A, the support = RkN (acting upward)
The principle is stated mathematically as:
sum of all upward forces = sum of all downward forces
R = 0.64kN + 0.3434kN = 0.9834kN
hence, the force on the support A is 0.9834kN
Explanation:
First to convert the masses in kg to forces, you multiply by acceleration due to gravity
F = mg
That is how the forces were obtained
Secondly, note that all weight acts downwards and the only force to balance the weights in this system will be the upward reaction from the support at point A
Now you can now apply the principle of forces in equilibrium as stated above to get the unknown force.
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Answer:
(a) ΔU=747J
(b) γ=1.3
Explanation:
For (a) change in internal energy
According to first law of thermodynamics the change in internal energy is given as
ΔU=Q-W
Substitute the given values
ΔU=970J-223J
ΔU=747J
For(b) γ for the gas.
We can calculate γ by ratio of heat capacities of the gas
γ=Cp/Cv
Where Cp is the molar heat capacity at constant pressure
Cv is the molar heat capacity at constant volume
To calculate γ we first need to find Cp and Cv
So
For Cp
As we know
Q=nCpΔT
Cp=(Q/nΔT)
From relation of Cv and Cp we know that
Cp=Cv+R
Where R is gas constant equals to 8.314J/mol.K
So
So
γ=Cp/Cv
γ=[(37J/mol.K) / (28.687J/mol.K)]
γ=1.3
The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.
Generally, the relationship between temperature, density and rate of vertical pressure is given as;
where;
- <em>ρ is density</em>
- <em>T is temperature</em>
- <em>dP is rate of change of vertical pressure</em>
Thus, from the formula above, we can conclude the following relationship between temperature, density and the rate of vertical pressure change in spatial pattern of heights.
The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.
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Answer:
F = 768 N
Explanation:
It is given that,
Speed of the elevator, v = 3.2 m/s
Grain drops into the car at the rate of 240 kg/min,
We need to find the magnitude of force needed to keep the car moving constant speed. The relation between the momentum and the force is given by :
Since, the speed is constant,
F = 768 N
So, the magnitude of force need to keep the car is 768 N. Hence, this is the required solution.
Answer : The value of the constant for a second order reaction is,
Explanation :
The expression used for second order kinetics is:
where,
k = rate constant = ?
t = time = 17s
= final concentration = 0.0981 M
= initial concentration = 0.657 M
Now put all the given values in the above expression, we get:
Therefore, the value of the constant for a second order reaction is,