Answer:
Yes, x(t)+C is also a solution of given equation.
Step-by-step explanation:
We are given that x(t) is a solution of the equation x'=f(x)
We have to show that x(t+c) is also a solution of given equation and check x(t)+c is a solution of equation.
Suppose x'=1
Integrating on both sides
Then , we get
Where C is integration constant.
Now, t replace by t+c
Then, we get
because c+C=K
Different w.r.t then we get
Therefore, x(t+c) is also solution because it satisfied the given equation.
Now, x(t)+C=t+(c+C)=t+L where L=c+C=Constant
Differentiate w.r.t time
Then, we get
Yes, x(t)+C is also solution of given equation because it satisfied given equation
Answer:
Step-by-step explanation:
we know that
If rectangle ABCD is similar to rectangle ZBXY
then
the ratio of their corresponding sides is equal and is called the scale factor
so
in this problem we have
Substitute the values and solve for CD
F(x) = 8 - 10xg(x) = 5x + 4
(fg)(x) = (8 - 10x)(5x + 4)
(fg)(x) = 40x + 32 - 50x^2 - 40x
(fg)(x) = 32 - 50x^2
(fg)(-2) = 32 - 50(-2)^2
(fg)(-2) = 32 - 200
(fg)(-2) = -168
Answer:
17.5%
Step-by-step explanation:
Hope this helps! Happy Trails!