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makvit [3.9K]
3 years ago
9

Question 2 of 5

Chemistry
2 answers:
alex41 [277]3 years ago
7 0
Precision relates to how close the answers are to each other, so I’d think it would be D because of the limited range between data points.
belka [17]3 years ago
6 0
A Group c 32.1 g 35.0 g 24.0 g
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When a 1.00 L sample of water from the surface of the Dead Sea (which is more than 400 meters below sea level and much saltier t
Harlamova29_29 [7]

Answer: Molarity of MgCl_2 in the original sample was 1.96M

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{\text{no of moles}}{\text{Volume in L}}

{\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{186g}{95g/mol}=1.96

Now put all the given values in the formula of molarity, we get

Molarity=\frac{1.96}{1.00L}

Molarity=1.96mol/L

Thus molarity of MgCl_2 in the original sample was 1.96M

4 0
3 years ago
Do ghosts exists ?? ...​
Nesterboy [21]

Answer:

no

Explanation:

it is human imagination about scary things that brought about ghost

5 0
3 years ago
Q1- Classify each of the molecules given below by molecular geometry.
Ludmilka [50]
It would be carbon dioxide codd2 for the molecules
3 0
2 years ago
A solution is prepared by dissolving 0.23 mol of chloroacetic acid and 0.27 mol of sodium chloroacetate in water sufficient to y
Sergio [31]

Answer:

c. chloroacetate ion

Explanation:

The chloroacetic acid, ClCH₂CO₂H, is a weak acid with Ka = 1.36x10⁻³. When this weak acid is in solution with its conjugate base, ClCH₂CO₂⁻ (From sodium chloroacetate) a buffer is produced. The addition of a strong acid as the HCl produce the following reaction

HCl + ClCH₂CO₂⁻ → ClCH₂CO₂H + Cl⁻.

Where the acid reacts with the chloroacetate ion to produce more chloroacetic acid

That means, the HCl reacts with the chloroacetate ion present in the buffer solution

Right answer is:

<h3>c. chloroacetate ion</h3>
8 0
3 years ago
Calculate the molarity of the solution formed when 0.72 moles of CaBr2 is dissolved in 1.50 L water.
xxTIMURxx [149]

Answer:

The molarity of the formed CaBr2 solution is 0.48 M

Explanation:

Step 1: Data given

Number of moles CaBr2 = 0.72 moles

Volume of water = 1.50 L

Step 2: Calculate the molarity of the solution

Molarity of CaBr2 solution = moles CaBr2 / volume water

Molarity of CaBr2 solution = 0.72 moles / 1.50 L

Molarity of CaBr2 solution = 0.48 mol / = 0.48 M

The molarity of the formed CaBr2 solution is 0.48 M

4 0
3 years ago
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