246 g KMnO4
Mass = 38.5 g water × (6.38 g KMnO4/100 g water) = 246 g KMnO4
1)
HI(aq) → H⁺(aq) + I⁻(aq)
So this is an Arrhenius acid because it releases H⁺.
2)
LiOH(s) → Li⁺ + OH⁻
So this is an Arrhenius base because it releases OH⁻
Answer:
62.98 % of the sample of hydrate is water
Explanation:
Step 1: Data given
Mass of the sample of a hydrate of sodium carbonate (Na2CO3) = 2.026 grams
After heating, the mass of the sample is 0.750 g
Molar mass H2O = 18.02 g/mol
Step 2: Calculate mass of water
Mass water = mass of hydrate - mass of sample after heating
Mass water = 2.026 grams - 0.750 grams
Mass water = 1.276 grams
Step 3: Calculate mass % percent of water
Mass % of water = (mass of water / total mass hydrate) * 100 %
Mass % of water = (1.276 grams / 2.026 grams) *100 %
Mass % of water = 62.98 %
62.98 % of the sample of hydrate is water
The object and description that matches is Object 2 and T.
Object 1 has no matching description.
<h3>Fish Aquarium Filter </h3>
A Fish aquarium filter is a filter whose function is to clean the water of debris, removes the toxic buildup of ammonia and nitrates, and aerates the water so that fish can in a conducive environment and breathe properly
<h3>Engine Oil Filter</h3>
An engine oil filter is a filter whose function is to filter and remove contaminants that may be present in the engine oil, transmission oil, lubricating oil, or hydraulic oil in order for proper functioning of the engine.
Therefore, the object and description that matches is Object 2 and T.
Object 1 has no matching description.
Learn more about filters and their uses at: brainly.com/question/10719424
