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Katarina [22]
3 years ago
14

Can someone help me write an equation and solve it for this word problem?

Mathematics
2 answers:
Yanka [14]3 years ago
6 0
30/5=6+2=8 
Eight would be the number 

Papessa [141]3 years ago
3 0

The number is 8, because if 2 is subtracted from 8 and 8 - 2 = 6 then 6 * 5 = 30

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natima [27]
Answer is c 10 eliminate the decimal l
6 0
4 years ago
What is a difference of squares that has a factor of x+8?
uysha [10]

Answer:

x^2 - 64

Step-by-step explanation:

A difference of squares is a special product in the form (a^2 - b^2)..their factored form is (a - b)(a + b)..

Thus here a = x and b = 8, thus if x + 8 is a factor, then x - 8 is also a factor..

(x + 8)(x - 8) <-- expand this out using difference of squares rules..

= (x)^2 - (8)^2 

= x^2 - 64 <-- answer...

You could also expand that using FOIL (FOIL - first, outer, inner, last)..

(x + 8)(x - 8) 

= (x)(x) + (x)(-8) + (8)(x) + (8)(-8) 

= x^2 - 8x + 8x - 64 <-- the -8x and 8x cancels out..leaving you with..

= x^2 - 64

7 0
3 years ago
Read 2 more answers
Which expression is equivalent to (- 2c / d^2)^3
nikdorinn [45]

-8c^3/d^6 is equivalent to the expression

4 0
3 years ago
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The density of ice is approximately 0.92 g/cm3 . If a block of ice has a volume of 2300 cm3, what is its mass?
Mumz [18]

Answer:

The mass of the ice block is 2116 grams ⇒ a

Step-by-step explanation:

The formula of density is p=\frac{m}{V} , where m is the mass and V is the volume

To find the mass from this formula multiply both sides by V,

then m = p.V

∵ The density of ice is approximately 0.92 g/cm³

∴ p = 0.92

- That means the mass of 1 cm³ is 0.92 g

∵ The volume of an ice block is 2300 cm³

∴ V = 2300

- Use the formula of the mass

∵ m = p.V

- Substitute the values of p and V in it

∴ m = (0.92)(2300)

∴ m = 2116 grams

The mass of the ice block is 2116 grams

7 0
3 years ago
4- What are the different waysto solve a quadratic? List examples of each
TiliK225 [7]
I know of two ways to solve quadratic equations. The first is through factoring. Let us take the example (x^2)+2x+1=0. We can factor this equation out and the factors would be (x+1)(x+1)=0. To solve for the roots, we equate each factor to 0, that is

x+1=0; x+1=0

In this case, the factors are the same so the root of the equation is

x=1.

The other way is to use the quadratic formula. The quadratic formula is given as [-b(+-)sqrt(b^2-4ac)]/2a where, using our sample equation above, a=1, b=2 and c=1. Substitute these to the formula, and you will get the same answer as the method above.
8 0
3 years ago
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