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posledela
3 years ago
14

Need to know the answer to this again

Mathematics
1 answer:
Tasya [4]3 years ago
4 0
R = dt
/d    /d
R/d = t

I think again
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is it Possibly 3 yards?

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Solve for x.<br> 2x² +21x-61 = (x+7)²<br><br> Please
Ymorist [56]

Answer:

x = \frac{-7 +\sqrt{489} }{2}

x = \frac{-7 - \sqrt{489} }{2}

Step-by-step explanation:

2x² +21x-61 = (x+7)²

expand

2x² + 21x - 61 = x² + 14x +49

move everything to one side

x² + 7x - 12 = 0

use quadratic formula

x = \frac{-b +- \sqrt{b^{2}-4ac } }{2a}

plug in the values

x = \frac{-7 +- \sqrt{7^{2}-4(1)(-110) } }{2(1)}

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x = \frac{-7 +- \sqrt{49-4(1)(-110) } }{2}

x = \frac{-7 +- \sqrt{49 + 440 } }{2}

x = \frac{-7 +- \sqrt{489} }{2}

7 0
2 years ago
Read 2 more answers
How does the graph of f(x)=3lx+2l+4 relate to its parent function?
Sergeeva-Olga [200]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;&#10;\begin{array}{rllll} &#10;% left side templates&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}&#10;\\\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\end{array}

\bf \begin{array}{llll}&#10;&#10;&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}&#10;\end{array}

now, with that template above in mind, let's see this one

\bf parent\implies f(x)=|x|&#10;\\\\\\&#10;\begin{array}{lllcclll}&#10;f(x)=&3|&1x&+2|&+4\\&#10;&\uparrow &\uparrow &\uparrow &\uparrow \\&#10;&A&B&C&D&#10;\end{array}


A=3, B=1,  shrunk by AB or 3 units, about 1/3
C=2,          horizontal shift by C/B or 2/1 or just 2, to the left
D=4,          vertical shift upwards of 4 units

check the picture below

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3 years ago
How do you solve 163-x= -52
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now it looks like -x=-215

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5 0
3 years ago
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(6)(1/4) + 14(1/4)
1.5 + 14(1/4)
1.5 + 3.5
5
7 0
3 years ago
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