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Wittaler [7]
3 years ago
10

Show that (x-5) is a factor of x^3-3x^2-13x+15

Mathematics
1 answer:
mario62 [17]3 years ago
6 0

Answer:

sorry not in that grade

Step-by-step explanation:

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Find the perimeter of the rectangle
kifflom [539]

Answer:

22x + 24

Step-by-step explanation:

7x+9+7x+9+4x+3+4x+3

11x + 18 + 11x + 6

Mark brainliest please!

3 0
2 years ago
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Help plz do those blank ones plz it would mean alot of help
Korvikt [17]
The second in the top row is this:
42.4-1.5(TIMES)3.1
     42.4-46.5
           -4.1

6 0
3 years ago
Write an equivalent expression for (3m - 6)(8m2 - 40m - 5).​
ycow [4]

Answer:

24m3−168m2+225m+30

Step-by-step explanation:

(3m+−6)(8m2+−40m+−5)

=(3m)(8m2)+(3m)(−40m)+(3m)(−5)+(−6)(8m2)+(−6)(−40m)+(−6)(−5)

=24m3−120m2−15m−48m2+240m+30

=24m3−168m2+225m+30

4 0
3 years ago
Which of the following is the general term for the sequence a, -a, a, -a, . . . ?
Nataly_w [17]

Answer:

a(-1)^(n-1).

Step-by-step explanation:

This is a Geometric Sequence with common ratio r = -1.

The general term is a(-1)^(n-1).

5 0
3 years ago
Questions 16-17 | Math 1 - 0 points Solve the graph Help needed !!
iris [78.8K]

Answer:

16) The area of the circle is 25.1 units²

17) JKLM is a parallelogram but not a rectangle

Step-by-step explanation:

16) Lets talk about the area of the circle

- To find the area of the circle you must find the length of the radius

- In the problem you have the center of the circle and a point on

 the circle, so you can find the length of the radius by using the

 distance rule

* Lets solve the problem

∵ The center of the circle is (1 , 3)

∵ The point on the circle is (3 , 5)

- Using the rule of the distance between two points

* Lets revise it

- The distance between the two points (x1 , y1) and (x2 , y2) is:

 Distance = √[(x2 - x1)² + (y2 - y1)²]

∴ r = √[(3 - 1)² + (5 - 3)²] = √[4 + 4] = √8 = 2√2 units

∵ The area of the circle = πr²

∴ The area of the circle = π (2√2)² = 8π = 25.1 units²

* The area of the circle is 25.1 units²

17) To prove a quadrilateral is a parallelogram, prove that every

     to sides are parallel or equal or the two diagonal bisect

     each other

* The parallelogram can be rectangle if two adjacent sides are

  perpendicular to each other (measure of angle between them is 90°)

 or its diagonals are equal in length

- The parallel lines have equal slopes, then to prove the

  quadrilateral is a parallelogram, we will find the slopes of

  each opposite sides

* Lets find from the graph the vertices of the quadrilateral

∵ J = (0 ,2) , K (2 , 5) , L (5 , 0) , M (3 , -3)

- The opposite sides are JK , ML and JM , KL

- The slope of any line passing through point (x1 , y1) and (x2 , y2) is

 m = (y2 - y1)/(x2 - x1)

∵ The slop of JK = (5 - 2)/(2 - 0) = 3/2 ⇒ (1)

∵ The slope of LM = (-3 - 0)/(3 - 5)= -3/-2 = 3/2 ⇒ (2)

- From (1) and (2)

∴ JK // LM

∵ The slope of KL = (0 - 5)/(5 - 2) = -5/3 ⇒ (3)

∵ The slope of JM = (-3 - 2)/(3 - 0)= -5/3 ⇒ (4)

- From (3) and (4)

∴ KL // JM

∵ Each two opposite sides are parallel in the quadrilateral JKLM

∴ It is a parallelogram

- The product of the slopes of the perpendicular line is -1

* lets check the slopes of two adjacent sides in the JKLM

∵ The slope of JK = 3/2 and the slope of KL = -5/3

∵ 3/2 × -5/3 = -5/2 ≠ -1

∴ JKLM is a parallelogram but not a rectangle

4 0
3 years ago
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