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kati45 [8]
3 years ago
13

3.45 x 10^20 molecules of sulfur dioxide to miles of sulfur dioxide

Chemistry
1 answer:
topjm [15]3 years ago
8 0
(3.45 x 10^20 molecules of sulfur dioxide ) x \frac{1 mole sulfur dioxide}{6.022x10^23 molecules sulfur dioxide} = 5.73x10^-4 mole of sulfur dioxide
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3 years ago
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The oxidation state of N changes from +2 to 0 while that of C changed from +2 to +4.

<h3>Oxidation and reduction</h3>

Oxidation is defined as an increase in oxidation number of the addition of oxygen while reduction is a decrease in oxidation number or removal of oxygen.

In the reaction shown by the equation, the oxidation number of N in NO changed from +2 to 0 in N_2 while that of C in CO changed from +2 to +4 in CO_2.

Thus, NO is acting as the oxidizing agent while CO is acting is the reducing agent.

More on oxidation and reduction can be found here: brainly.com/question/13699873

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4 0
2 years ago
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8 0
3 years ago
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Answer:

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