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kati45 [8]
3 years ago
13

3.45 x 10^20 molecules of sulfur dioxide to miles of sulfur dioxide

Chemistry
1 answer:
topjm [15]3 years ago
8 0
(3.45 x 10^20 molecules of sulfur dioxide ) x \frac{1 mole sulfur dioxide}{6.022x10^23 molecules sulfur dioxide} = 5.73x10^-4 mole of sulfur dioxide
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For the reaction
s2008m [1.1K]

Answer:

0.558mole of SO₃

Explanation:

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Unknown:

Maximum amount of SO₃

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So we simply compare the molar relationship between sulfur and product formed to solve the problem:

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