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kati45 [8]
3 years ago
13

3.45 x 10^20 molecules of sulfur dioxide to miles of sulfur dioxide

Chemistry
1 answer:
topjm [15]3 years ago
8 0
(3.45 x 10^20 molecules of sulfur dioxide ) x \frac{1 mole sulfur dioxide}{6.022x10^23 molecules sulfur dioxide} = 5.73x10^-4 mole of sulfur dioxide
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Is 2 KNO₃ + H₂CO₃ → K₂CO₃ + 4 HNO₃ a balanced equation
krok68 [10]

Hey there!

The elements in this equation are K, N, O, H, and C.

Let's count how many of each are on each side to see if it is balanced.

K: 2 on the left, 2 on the right.

<em>N: 2 on the left, 4 on the right. </em>

<em>O: 9 on the left, 6 on the right. </em>

<em>H: 2 on the left, 4 on the right. </em>

C: 1 on the left, 1 on the right.

Notice that there are different amounts of N, O, and H on the left side and the right side.

This means that the equation is not balanced.

Hope this helps!

6 0
3 years ago
Please help on 8 thank youuuuuuuuuu
enyata [817]

Answer:

b)5l x 10kg  c)10kg + 9l   (Not sure for the last 1)

6 0
3 years ago
"calculate the ratio of the velocity of hydrogen molecules to the velocity of carbon dioxide molecules at the same temperature"
Ne4ueva [31]

Answer: 1:4.69

Explanation:

The ratio can be expressed as:

Ua/Ub= √(Mb/Ma)

Where Ua/Ub is the ratio of velocity of hydrogen to carbon dioxide and Ma is the molecular mass of hydrogen gas= 2

Mb is the molecular mass of CO2 = 44

Therefore

Ua/Ub= √(44/2)

Ua/Ub = 4.69

Therefore the ratio of velocity of hydrogen gas to carbon dioxide = 1:4.69

which implies hydogen is about 4.69 times faster than carbon dioxide.

8 0
4 years ago
Simple question plzz help
PSYCHO15rus [73]

Answer:

a  

Explanation:

3 0
3 years ago
Read 2 more answers
Adding O2 to the reaction 6CO2 + 6H2O C6H12O6 + 6O2. WHICH WAY WILL THE REACTION SHIFT?
Oxana [17]

Answer:

The reaction will shift to the left to produce more reactants.

Explanation:

According to the Le- Chatelier principle,

At equilibrium state when stress is applied to the system, the system will behave in such a way to nullify the stress.

The equilibrium can be disturb,

By changing the concentration

By changing the volume

By changing the pressure

By changing the temperature

Consider the following chemical reaction.

Chemical reaction:

6CO₂ +  6H₂O  ⇄  C₆H₁₂O₆ + 6O₂

In this reaction the equilibrium is disturb by increasing the concentration of Product.

When the concentration of product is increased the system will proceed in backward direction in order to regain the equilibrium. Because when product concentration is high it means reaction is not on equilibrium state. As the concentration of O₂  increased the reaction proceed in backward direction to regain the equilibrium state and more reactant is formed.

4 0
3 years ago
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