for the sn1 reaction, draw the major organic product, identify the nucleophile, substrate, and leaving group, and determine the
1 answer:
C4H9OH is the substrate, Br- is the nucleophile and H2O is the leaving group.
In an SN1 reaction, the rate limiting step is the formation of the carbocation. The carbocation is formed as water which is the leaving group departs. After the leaving group departs, the nucleophile (Br-) attacks to yield the major organic product. The protonation of the -OH group is the first step in the reaction.
It then follows that, C4H9OH is the substrate, Br- is the nucleophile and H2O is the leaving group.
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Explanation:
Formula to calculate hybridization is as follows.
Hybridization =
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
So, hybridization of is as follows.
Hybridization =
=
= 2
Hybridization of is sp. Therefore,
is a linear molecule. There will be only two electron groups through which Be is attached.
Similarly, hybridization of is calculated as follows.
Hybridization =
=
= 5
Therefore, hybridization of is
is also a linear molecule. Though there are three lone pair of electrons present on a xenon atom and it is further attached with fluorine atoms through two electron pairs. Hence, there are in total five electron groups.
Thus, we can conclude that out of the given options is the correct examples of linear molecules for five electron groups.