Answer:
v = 34.62 L
Explanation:
Given data:
Moles of H₂ = 2.50 mol
Temperature of gas = -20.0°C
Pressure of gas = 1.5 atm
Volume of gas = ?
Solution:
Formula:
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
-20 + 273 = 253 K
Now we will put the values in formula.
1.5 atm × v = 2.50 mol ×0.0821 atm.L/ mol.K × 253 K
1.5 atm × v = 51.93 atm.L
v = 51.93 atm.L/1.5 atm
v = 34.62 L
The volume of hydrogen is 34.62 L.
Answer:
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Combination
Hope this helps :)
Molar mass:
O2 = 31.99 g/mol
C8H18 = 144.22 g/mol
<span>2 C8H18(g) + 25 O2(g) = 16 CO2(g) + 18 H2O(g)
2 x 144.22 g --------------- 25 x 31.99 g
10.0 g ----------------------?? ( mass of O2)
10.0 x 25 x 31.99 / 2 x 144.22 =
7997.5 / 288.44 => 27.72 g of O2
hope this helps!
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