Question

A sample of gas occurs 9.0mL at a pressure of 500mmHg. A new volume of the same sample is at 750mmHg. Use two significant figures in answer on volume.

Answer 1

Answer:

$\large \boxed{\text{6.0 mL} }$

Explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

$p_{1}V_{1} = p_{2}V_{2}$

Data:

$\begin{array}{rcrrcl}p_{1}& =& \text{500 mmHg}\qquad & V_{1} &= & \text{9.0 mL} \\p_{2}& =& \text{750 mmHg}\qquad & V_{2} &= & ?\\\end{array}$

Calculations:  

$\begin{array}{rcl}500 \times 9.0 & =& 750V_{2}\\4500 & = & 750V_{2}\\V_{2} & = &\dfrac{4500}{750}\\\\& = & \textbf{6.0 mL}\\\end{array}\\\text{The volume of the gas is } \large \boxed{\textbf{6.0 mL}}$