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oee [108]
3 years ago
11

Visitors to a carnival are invited to guess the number of beans in a jar. The person who guesses the correct number wins $300 if

multiple people guess correctly, the prize will be divided evenly among them. What is the relationship between the number of people who guess correctly and the amount of money each person will recieve
Mathematics
1 answer:
andrew11 [14]3 years ago
5 0

The relationship between the two variables is inverse proportionality, that is, the greater the number of people, the less the amount of money earned.

Since visitors to a carnival are invited to guess the number of beans in a jar, and the person who guesses the correct number wins $ 300, but if multiple people guess correctly, the prize will be divided evenly among them, to determine what is the relationship between the number of people who guess correctly and the amount of money each person will recieve the following logical reasoning must be performed:

Since the prize is a fixed number, 300, it is a value that will not change. In turn, the more people who have guessed right, the lower the amount of money that each of them will win (because the number 300 will be divided by a greater number).

Therefore, the relationship between the two variables is inverse proportionality, that is, the greater the number of people, the less the amount of money earned.

Learn more in brainly.com/question/2548537

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Dentify on which quadratic function is positive.
Olin [163]

Answer:

\textsf{$y = 2x^2 - 17x + 30$: \quad $\left(-\infty, \dfrac{5}{2}\right) \cup (6, \infty)$}

\textsf{$y = - x^2 - 6x - 8$: \quad $\left(-\infty, -4\right) \cup (-2, \infty)$}

Step-by-step explanation:

A function is positive when it is <u>above the x-axis</u>, and negative when it is <u>below the x-axis</u>.

---------------------------------------------------------------------------------

<u>Given quadratic equation</u>:

y = 2x^2 - 17x + 30

Factor the equation:

\implies y = 2x^2 - 17x + 30

\implies y = 2x^2 - 5x-12x + 30

\implies y=x(2x-5)-6(2x-5)

\implies y=(x-6)(2x-5)

The x-intercepts of the parabola are when y = 0.

To find the <u>x-intercepts</u>, set each factor equal to zero and solve for x:

\implies x-6=0 \implies x=6

\implies 2x-5=0 \implies x=\dfrac{5}{2}

Therefore, the x-intercepts are x = ⁵/₂ and x = 6.

The leading coefficient of the given function is positive, so the <u>parabola opens upwards</u>.  

The function is positive when it is <u>above the x-axis</u>.

Therefore, the function is positive for the values of x less than the smallest x-intercept and more than the largest x-intercept:

  • \textsf{Solution: \quad $x < \dfrac{5}{2}$ \;and \;$x > 6$}
  • \textsf{Interval notation: \quad $\left(-\infty, \dfrac{5}{2}\right) \cup (6, \infty)$}

---------------------------------------------------------------------------------

<u>Given quadratic equation</u>:

y = - x^2 - 6x - 8

Factor the equation:

\implies y = - x^2 - 6x - 8

\implies y = -(x^2 +6x +8)

\implies y = -(x^2 +4x +2x+8)

\implies y = -((x(x+4)+2(x+4))

\implies y = -(x+4)(x+2)

The x-intercepts of the parabola are when y = 0.

To find the <u>x-intercepts</u>, set each factor equal to zero and solve for x:

\implies x+4=0 \implies x=-4

\implies x+2=0 \implies x=-2

Therefore, the x-intercepts are x = -4 and x = -2.

The leading coefficient of the given function is negative, so the <u>parabola opens downwards</u>.  

The function is negative when it is <u>below the x-axis</u>.

Therefore, the function is negative for the values of x less than the smallest x-intercept and more than the largest x-intercept:

  • \textsf{Solution: \quad $x < -4$ \;and \;$x > -2$}
  • \textsf{Interval notation: \quad $\left(-\infty, -4\right) \cup (-2, \infty)$}

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Answer:

Confidence interval: (21.9, 32.9).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 26 - 1 = 25

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The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.485\frac{11.2}{\sqrt{26}} = 5.5

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