Step- by - step - explaination
D) #recombinant=116+601+4+2+113+625=1462
#nonrecombinant=2538+2708=5246
RF=R/(N+R)=1462/6708=0.2
E) I=1-Q
I-interference
Q-coefficient of coincidence
Q=O2Xo/E2xo(2xo-double crossovers)
O2xo=6
P=(distance from C1 to Sh/100)*(distance from Sh to Wx/100)
=(3.38/100)*(18.28/100)=0.006
E2xo=0.006*6708=40.248
Q=6/40.248=0.15
I=1-0.15=0.85
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Anwser
Thank you so much for posting this, I need it for my class. :)
May I have Brainliest?
Answer:
12:3:1
Explanation:
<em>The typical F2 ratio in cases of dominant epistasis is 12:3:1.</em>
<u>The epistasis is a form of gene interaction in which an allele in one locus interacts with and modifies the effects of alleles in another locus</u>. There are different types of epistasis depending on the type of alleles that are interacting. These include:
- Dominant/simple epistasis: Here, a dominant allele on one locus suppresses the expression of both alleles on another locus irrespective of whether they are dominant or recessive. Instead of the Mendelian dihybrid F2 ratio of 9:3:3:1, what is obtained is 12:3:1. Examples of this type of gene interaction are found in seed coat color in barley, skin color in mice, etc.
- Other types of epistasis include <em>recessive epistasis (9:3:4), dominant inhibitory epistasis (13:3), duplicate recessive epistasis (9:7), duplicate dominant epistasis (15:1), and polymeric gene interaction (9:6:1).</em>