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Phoenix [80]
3 years ago
8

A tourist boat is used for sightseeing in a nearby river. The boat travels 2.4 miles downstream and in the same amount of time,

it travels 1.8 miles upstream. If the boat travels at an average speed of 21 miles per hour in the still water, find the current of the river.
Mathematics
2 answers:
topjm [15]3 years ago
7 0

Answer: the current of the river is 3 mph.

Step-by-step explanation:

Let x represent the current of the river.

The boat travels 2.4 miles downstream. Assuming it travelled with the current of the river. If the boat travels at an average speed of 21 miles per hour in the still water, it means that the total speed at which the boat travelled downstream is

(21 + x) mph

Time = distance/speed

Time taken to travel downstream is

2.4/(21 + x)

it travels 1.8 miles upstream. Assuming it travelled against the current of the river. it means that the total speed at which the boat travelled upstream is

(21 - x) mph

Time taken to travel upstream is

1.8/(21 - x)

Since the time taken to travel upstream and downstream is the same, then

2.4/(21 + x) = 1.8/(21 - x)

Cross multiplying, it becomes

2.4(21 - x) = 1.8(21 + x)

50.4 - 2.4x = 37.8 + 1.8x

2.4x + 1.8x = 50.4 - 37.8

4.2x = 12.6

x = 12.6/4.2

x = 3 mph

erastovalidia [21]3 years ago
4 0

Answer and Step-by-step explanation:

Greetings!

Let's~answer~your~question!

Let~ x ~miles~ per~ hour~ be ~the~ current~ of~ the~ river.

<em>1. The boat travels 2.4 miles downstream with the speed of (21+x) miles per hour. It takes him</em>

\frac{2.4}{21+x}~hours

<em>2. The boat travels 1.8 miles upstream with the speed of (21-x) miles per hour. It takes him</em>

<em></em>\frac{1.8}{21-x}~hours<em></em>

<em></em>

<em>3. The time is the same,so:</em>

<em></em>\frac{2.4}{21+x} =\frac{1.8}{21-x}<em></em>

<em></em>

<em></em>Now,~cross~multiply:<em></em>

<em></em>2.4(21-x)=1.8(21+x)<em></em>

<em></em>

<em></em>Multiply~by~10~now:<em></em>

<em></em>24(21-x)=1.8(21+x)<em></em>

<em></em>

<em></em>Divide~by~6:<em></em>

<em></em>4(21-x)=3(21+x)<em></em>

<em></em>84-4x=63+3x<em></em>

<em></em>84-63=3x+4x<em></em>

<em></em>7x=21<em></em>

<em></em>x=3<em></em>

<em></em>

<em>Thus, 3 miles per hour is your answer to the question.</em>

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MA_775_DIABLO [31]

There's a slight problem with your question, but we'll get to that...

Consecutive terms of the sequence are separated by a fixed difference of 21 (22 = 1 + 21, 43 = 22 + 21, 64 = 43 + 21, and so on), so the <em>n</em>-th term of the sequence, <em>a</em> (<em>n</em>), is given recursively by

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• <em>a</em> (<em>n</em>) = <em>a</em> (<em>n</em> - 1) + 21 … … … for <em>n</em> > 1

We can find the explicit rule for the sequence by iterative substitution:

<em>a</em> (2) = <em>a</em> (1) + 21

<em>a</em> (3) = <em>a</em> (2) + 21 = (<em>a</em> (1) + 21) + 21 = <em>a</em> (1) + 2×21

<em>a</em> (4) = <em>a</em> (3) + 21 = (<em>a</em> (1) + 2×21) + 21 = <em>a</em> (1) + 3×21

and so on, with the general pattern

<em>a</em> (<em>n</em>) = <em>a</em> (1) + 21 (<em>n</em> - 1) = 21<em>n</em> - 20

Now, we're told that the sum of some number <em>N</em> of terms in this sequence is 2332. In other words, the <em>N</em>-th partial sum of the sequence is

<em>a</em> (1) + <em>a</em> (2) + <em>a</em> (3) + … + <em>a</em> (<em>N</em> - 1) + <em>a</em> (<em>N</em>) = 2332

or more compactly,

\displaystyle\sum_{n=1}^N a(n) = 2332

It's important to note that <em>N</em> must be some positive integer.

Replace <em>a</em> (<em>n</em>) by the explicit rule:

\displaystyle\sum_{n=1}^N (21n-20) = 2332

Expand the sum on the left as

\displaystyle 21 \sum_{n=1}^N n-20\sum_{n=1}^N1 = 2332

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\displaystyle\sum_{k=1}^n1=\underbrace{1+1+\cdots+1}_{n\text{ times}}=n

\displaystyle\sum_{k=1}^nk=1+2+3+\cdots+n=\frac{n(n+1)}2

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Solve for <em>N</em> :

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21 <em>N</em> ² - 19 <em>N</em> - 4664 = 0

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<em>N</em> = (19 ± √392,137)/42 ≈ -14.45 or 15.36

so there is no positive integer <em>N</em> for which the first <em>N</em> terms of the sum add up to 2332.

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