Answer:
B) -125a^11
Step-by-step explanation:
(-5a^2)^3·a^5 = (-5)^3·a^6·a^5
= (-5)^3·a^(2·3)·a^5
= (-5)^3·a^6·a^5
= -125·a^(6+5)
= -125·a^11 . . . . matches choice B
_____
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
Answer:
B. 6i√6
General Formulas and Concepts:
<u>Algebra II</u>
- Imaginary Numbers: √-1 = i
Step-by-step explanation:
<u>Step 1: Define expression</u>
√-216
<u>Step 2: Simplify</u>
- Factor: √-1 · √216
- Simplify: i · 6√6
- Multiply: 6i√6
Answer:
6.5 x 10^6 To answer this question, you need to divide the mass of the sun by the mass of mercury. So 2.13525 x 10^30 / 3.285 x 10^23 = ? To do the division, divide the mantissas in the normal fashion 2.13525 / 3.285 = 0.65 And subtract the exponents. 30 - 23 = 7 So you get 0.65 x 10^7 Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving 6.5 x 10^6 So the sun is 6.5 x 10^6 times as massive as mercury.
:}
Answer:
2
Step-by-step explanation:
hope this helps
Answer:
7×11=77
Step-by-step explanation:
7
9+2=11
7×11=77
