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Tom [10]
3 years ago
13

Determine the smallest 6 digit number which is exactly divisible by 8,15,and21

Mathematics
1 answer:
ch4aika [34]3 years ago
3 0
Find the least common multiple of 8, 15, and 21. . . . . . It's 280 .

So all the numbers divisible by 8, 15, and 21 are all the multiples of 280.

The smallest 6-digit number is 100,000 .

100,000 / 280 = 357.1 , so the next whole-number multiple is the 358th one.

280 x 358 = <u>100,240</u> .

You can tell right away that this is the smallest one that qualifies,
because if you take away 280 and go to the next smaller multiple,
it won't have 6 digits anymore.
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Consider the function f(x)=-2x+5 what is f(5) enter your answer in the box
Oliga [24]

The value of f(5) is f(5)=-5

Step-by-step explanation:

The function is f(x)=-2x+5

To find f(5) substitute x=5 in f(x)=-2x+5

f(5)=-2(5)+5

Multiplying the terms, we get,

f(5)=-10+5

Adding the terms, we get,

f(5)=-5

Thus, the value of f(5) is f(5)=-5

8 0
4 years ago
Select two choices that are true about the function f(x)=23x+14/x
WINSTONCH [101]

Answer:

There is an asymptote at x = 0

There is an asymptote at y = 23

Step-by-step explanation:

Given the function:

(23x+14)/x

Vertical asymptote is gotten by equating the denominator to zero

Since the denominator is x, hence the vertical asymptote is at x = 0. This shows that there is an asymptote at x = 0

Also for the horizontal asymptote, we will take the ratio of the coefficient of the variables in the numerator and denominator

Coefficient of  x at the numerator = 23

Coefficient of x at the denominator = 1

Ratio = 23/1 = 23

This means that there is an asymptote at y = 23

8 0
3 years ago
Calculate the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass of 1 m^3 of water to be 1000 kg
Lady bird [3.3K]

Answer:

1813.137 KJ

Step-by-step explanation:

potential energy of the body = mgH

where m is mass in Kg , g= 9.81 m/sec^2 and H= height in m

here m= 1000 kg, g= 9.81 m/s^2  and H= 607 feet = 607×0.305= 185.135 m

hence the potential energy p= 1000×9.81×185.135= 1813137.2 J

= 1813.137 KJ

hence the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass as 1000 kg is = 1813.137 KJ

4 0
4 years ago
Shannon went to an auto repair shop and paid $339.50, which included parts that cost $112 and 3.5 hours of labor. Joni went to a
QveST [7]

Answer:

im late but its d i hope

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Help please! i don't know what to do
Serhud [2]
I hope this helps you



9/9+18=x/x+10


9/27=x/x+10


1/3=x/x+10

3x=x+10

x=5


8 0
3 years ago
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