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3 years ago

Pls help mee for my hw worth branliest and a bunch of thxx

Mathematics

1 answer:

Marizza181 [45]3 years ago

7 0

I think the answer is letter c

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Mrs. Walker is instructing a team of students on designing the sailboat shown. Beth is working on the smaller sail, which is a r

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Answer: OPTION C.

Step-by-step explanation:

1. To solve this problem you must apply the Pythagorean Theorem, which is shown below:

$a^{2}=b^{2}+c^{2}$

Where a is the hypotenuse, and b and c are the legs of the triangle.

2. When you solve for one of the legs and substitute values, you obtain that the result is:

$b=\sqrt{a^{2}-c^{2}}\\b=\sqrt{(24.8ft)^{2}-(8ft)^{2}}\\b=23.5ft$

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Is 8 positive or negative

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Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE

eduard

Answer:

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

Step-by-step explanation:

Given the matrices

$A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}$

$B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}$

Calculating AB:

$\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}$

Multiply the rows of the first matrix by the columns of the second matrix

$=\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}$

$=\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}$

Hence,

$\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}$

Therefore,

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

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2 years ago

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