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alexgriva [62]
3 years ago
9

How many different breakfasts can you have at the local diner if you can select 3 different egg dishes​ (scrambled, fried,​ poac

hed), 4 choices of meat​ (steak, ham,​ bacon, sausage), 5 breads​ (white, wheat,​ rye, muffin,​ bagel), 6 juices​ (tomato, grape,​ apple, orange, mixed​ berry, vegetable​ cocktail), and 4 beverages​ (water, milk,​ coffee, tea)?
Mathematics
1 answer:
faltersainse [42]3 years ago
6 0

To find the total number of combinations, multiply all the choices together:

3 eggs x 4 meats x 5 breads x 6 juices x 4 beverages:

3 x 4 x 5 x 6 x 4 = 1,440 different breakfasts

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PLEASE HELP ME WITH THIS
Alik [6]

Answer:

  • x + y ≤ 600
  • 5x +7y ≥ 3500
  • it is possible

Step-by-step explanation:

a) We can write two inequalities, one for the number of tickets, and one for the necessary revenue.

  x + y ≤ 600 . . . . . . . limit imposed by available seating

  5x +7y ≥ 3500 . . . . required revenue to meet expenses

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b) For x = 330, the first inequality puts one limit on y:

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And the second inequality puts another limit on y:

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The number of tickets that must be sold to meet expenses is 265, which is less than the number that can be sold, 270. It is possible to meet expenses.

4 0
3 years ago
21 marbles out of N are blue; probability of getting a blue one = 30%
MissTica
Probability=\frac{desired}{total}
0.3=\frac{21}{N}
0.3N=21
N=\frac{21}{0.3}
N=70

There are 70 total marbles. 
4 0
3 years ago
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