16 balls.
Let's call x the total number of golf balls that Ricardo had before he lost the first 6 balls. (x - 6).
Then he bought 12 more and lost 4 so basically 12 - 4 = 8
Add that to the equation: (x-6) + 8
And now that he has 18 golf balls at end of the second day the total must add to 18.
Full equation: (x-6) + 8 = 18
(x-6) + 8 = 18
(x-6) = 18 - 8 <-- Transpose
(x-6) = 10
16 - 6 = 10 <-- What would x have to be inoder to make this equation true? 16!
So x = 16
16 is the number of golf balls the Ricardo began with.
Answer:
1/6
Step-by-step explanation:
There is only one side of the die with a number 4, and 6 possible outcomes. Therefore the answer is 1/6
X = y - 3
x + 3y = 13
x + 3y = 13 (replace x with y-3)
y - 3 + 3y = 13
4y - 3 = 13
4y = 13 + 3
4y = 16
y = 16/4
y = 4
x = y - 3
x = 4 - 3
x = 1
The answer is A. (1,4)
Answer:
<u><em>Answer is below</em></u>
Step-by-step explanation:
<u><em> Divide both sides by 3.</em></u>
