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4 years ago

The coordinates below represent two linear equations.

Mathematics

1 answer:

Vikki [24]4 years ago

5 0

0. The two lines are parallel because they have the same slope. You can find this by using the slope formula.

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Find the smallest zero for the function h(x)=4x^2-8x-60

cupoosta [38]

Your answer would be 3=x or 5=x
Hope this helps!
Have a nice day!

3 0

4 years ago

Use the quadratic formula to solve the equation. <br> x ^2 – 7 x –6 = 0<br> (Show work)

Vika [28.1K]

Given a quadratic equation

$ax^2+bx+c=0$

the quadratic formula states that the solutions are

$x_{1,2}=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plug your values to get

$x_{1,2}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot 1 \cdot (-6)}}{2\cdot 1}$

Which evaluates to

$\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot 1 \cdot (-6)}}{2\cdot 1} = \dfrac{7\pm\sqrt{73}}{2}$

So, the two solutions are

$x_1 = \dfrac{7+\sqrt{73}}{2},\quad x_2 = \dfrac{7-\sqrt{73}}{2}$

5 0

3 years ago

The definition of a circle uses the undefined term? ..

Naddika [18.5K]

Answer:

Plane

Step-by-step explanation:

or C

6 0

4 years ago

D²y/dx²=12x-12. express y in terms of x

Liono4ka [1.6K]

Answer:

y(x)=2x^3-6x^2+ax+b, a and b are constants

Step-by-step explanation:

d2y/dx2=12x-12, integrating both sides we get

dy/dx=6x^2-12x+a, where a is the integration constant.

Again integrating both sides, we get

y(x)=2x^3-6x^2+ax+b, where b is the integration constant

5 0

3 years ago

Solve the equation for [0,2pi]<br> cos2x=1/sqrt2

lapo4ka [179]

$cos(2x) = \frac{1}{\sqrt{2}}$
$cos(2x) = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}$
$cos(2x) = \frac{\sqrt{2}}{2}$
$cos(2x) = cos(45)$
$cos(x) = cos(22.5)$
$x = 22.5$

5 0

3 years ago