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xenn [34]
3 years ago
14

Solve the equation for [0,2pi] cos2x=1/sqrt2

Mathematics
1 answer:
lapo4ka [179]3 years ago
5 0
cos(2x) = \frac{1}{\sqrt{2}}
cos(2x) = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}
cos(2x) = \frac{\sqrt{2}}{2}
cos(2x) = cos(45)
cos(x) = cos(22.5)
x = 22.5
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The answer would be x ≠ 0

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