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xenn [34]
2 years ago
14

Solve the equation for [0,2pi] cos2x=1/sqrt2

Mathematics
1 answer:
lapo4ka [179]2 years ago
5 0
cos(2x) = \frac{1}{\sqrt{2}}
cos(2x) = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}
cos(2x) = \frac{\sqrt{2}}{2}
cos(2x) = cos(45)
cos(x) = cos(22.5)
x = 22.5
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If 2a - b = 4 , find a.
julia-pushkina [17]
<h2>Answer:  a = ¹/₂ (4 + b)</h2>

<h3>Step-by-step explanation:</h3>

To solve for 'a' we have to make it the subject of the equation. Since there are two unknowns ('a' & 'b'), we won't get a numerical value of 'a', but an expression in terms of the second unknown 'b'.

Since 2a - b = 4                    <em> [add 'b' to both sides]</em>

then          2a = 4 + b             <em>[divide both sides by 2 = multiplying by  ¹/₂]</em>

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marusya05 [52]

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2 years ago
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Andrei [34K]

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Inessa05 [86]

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