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xenn [34]
3 years ago
14

Solve the equation for [0,2pi] cos2x=1/sqrt2

Mathematics
1 answer:
lapo4ka [179]3 years ago
5 0
cos(2x) = \frac{1}{\sqrt{2}}
cos(2x) = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}
cos(2x) = \frac{\sqrt{2}}{2}
cos(2x) = cos(45)
cos(x) = cos(22.5)
x = 22.5
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Consider this quadratic equation:
zhenek [66]

Answer:

a=2

b=0

c=12

Step-by-step explanation:

The standard form of a quadratic equation is ax²+bx+c=0

Here's the given equation:

2x²+12=0

You might notice that the term bx is not there (there is just ax² and c). That means that b is 0.

The term 2x² is the term ax² in this equation. The coefficient in the term is 2, so that means that a is 2

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Hope this helps!

6 0
3 years ago
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diamong [38]
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(n + 7)(3)
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Quadratic formula<br> x2 + 3x - 5 = 0
FrozenT [24]

Answer:

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5 0
3 years ago
3 women push a stalled car. Each woman pushes with a 425 N force. What is the mass of the
iogann1982 [59]

Answer:

1,500 Kg

Step-by-step explanation:

Formual for froce is given by

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8 0
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