All categories

3 years ago

Please solve for x: :)

Mathematics

1 answer:

anygoal [31]3 years ago

7 0

Hello!

As you can see, the angles we are given make up a 90 degree angle. We have the equation below.

4x=90

To solve we just divide both sides by 4.

90/4=22.5
x=22.5

I hope this helps!

You might be interested in

Scsb17 what is -5 + 8x - 10

bogdanovich [222]

The answer is 5+8x i think

4 0

3 years ago

Read 2 more answers

okay so ive got a ton of piecewise function things and I really suck at them so maybe someone wants to help me? :D thanks giving

algol [13]

[] signs mean that the number is included in the domain and () mean that the number is not included. Now,

1. [-1,5)
Because x is greater than or equal to -1 (included) but less than 5 (excluded

2. [-5,13)
When we plug in x = -1, we get the minimum value of -5, which is included because its x-value was included. The, we plug in x = 5 to find the range's maximum and this is excluded because its x-value was excluded.

3. 218
x = 6 lies in the domain of the first function so we will use it to evaluate the value of x = 6. We do this by simply substituting x into the function.

4. 12
x = 9 is included in the domain of the second function and the value of the second function at all points is 12.

5. 103
x = 10 is included in the domain of the second function so we will use it to evaluate the value of x = 10. This is done by substituting x into the equation.

4 0

3 years ago

Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th

VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

$f(x)=16-\frac{x^2}{3}$

To find $f(-64)$ , we substitute $x=-64$ into the function.

$f(-64)=16-\frac{(-64)^2}{3}$

$f(-64)=16-\frac{4096}{3}$

$f(-64)=-\frac{4048}{3}$

To find $f(64)$ , we substitute $x=64$ into the function.

$f(64)=16-\frac{(64)^2}{3}$

$f(64)=16-\frac{4096}{3}$

$f(64)=-\frac{4048}{3}$

To find $f'(c)$ , we must first find $f'(x)$ .

$f'(x)=-\frac{2x}{3}$

This implies that;

$f'(c)=-\frac{2c}{3}$

$f'(c)=0$

$\Rightarrow -\frac{2c}{3}=0$

$\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}$

$c=0$

For this function to satisfy the Rolle's Theorem;

It must be continuous on $[-64,64]$ .

It must be differentiable on $(-64,64)$ .

and

$f(-64)=f(64)$ .

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

6 0

2 years ago

Read 2 more answers

The points plotted below are on the graph of a polynomial. Some of the roots to this polynomial are integers. Which of the follo

Vikki [24]

The only root is -2. The roots are where the function goes through the x-axis. This polynomial goes through in lots of places, but the only answer that matches is -2

8 0

3 years ago

Determine if the inequality is true or false: 3q < 18 if q = 6

kap26 [50]

Answer:

false

Step-by-step explanation:

it is because 3(6) which q=6 gives the answer of 18, so 18 can not be bigger than 18

3 0

2 years ago