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ICE Princess25 [194]
3 years ago
9

Solve this inequality: 12p + 7> 139

Mathematics
1 answer:
kirill [66]3 years ago
3 0
12p + 7\ \textgreater \  139 \\ \\ 12p \ \textgreater \  139 - 7 \ / \ subtract \ 7 \ from \ each \ side \\ \\ 12p \ \textgreater \  132 \ / \ simplify \\ \\ p \ \textgreater \   \frac{132}{12} \ / \ divide \ each \ side \ by \ 12 \\ \\ p \ \textgreater \  11 \ / \ simplify \\ \\

The final result is: A) p > 11
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How many Japanese yen are equal to $100?
disa [49]
If you mean american dollars (which you most likely do) then it would be:
100 = 12285.
1000 = 122850.
10.000 = 1228.10
hope i helped
3 0
3 years ago
Read 2 more answers
What is d if <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3d-2%7D%7B8%7D%20%3D%20-d%2B16%5Cfrac%7B1%7D%7B4%7D" id="TexFormula1" t
Harlamova29_29 [7]

Answer: d=12

Step-by-step explanation:

\displaystyle\\\frac{3d-2}{8} =-d+16\frac{1}{4} \\\\\frac{3d-2}{8} =-d+\frac{16*4+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{64+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{65}{4}

Multiply both parts of the equation by 8:

\displaystyle\\3d-2=(-d+\frac{65}{4} )(8)\\\\3d-2=-8d+65*2\\\\3d-2=-8d+130\\\\3d-2+2=-8d+130+2\\\\3d=-8d+132\\\\3d+8d=-8d+132+8d\\\\11d=132\\

Divide both parts of the equation by 11:

d=12

8 0
2 years ago
If L
BabaBlast [244]
Pythagorean's theorem says the hypotenuse of a triangle is A^2+B^2=C^2 in this case I'll put the L,W, and D so it's easy to understand. L^2+W^2=D^2 is the exact same formula as above and is how we will solve this. (30^2)+(10^2)=1000 then we take the square root since 1000=D^2, and we get 36.62 as D.
3 0
3 years ago
Which figures below are congruent?<br> 1 and 2<br> 2 and 3<br> 1 and 3<br> 2 and 4
zvonat [6]

Answer:

1 and 3

Step-by-step explanation:

since they both are equal shape with equal sizes.

4 0
3 years ago
From the graph; calculate: E=
Ket [755]
<h3>Answer:</h3>

c) 7π cm

<h3>Step-by-step explanation:</h3>

The length of an arc (s) is related to its central angle (θ) and the radius of the circle (r) by ...

... s = rθ . . . . . . . . . θ in radians

Here, the central angle measures are given in "grads". There are 400 grads in a circle, so 200 grads in π radians. To convert grads to radians, we multiply the number of grads by π/(200g).

Then the lengths of the arcs are ...

... arc AB = (20 cm)·(50g·(π/(200g))) = 5π cm

... arc BC = (10 cm)·(40g·(π/(200g))) = 2π cm

E = arc AB + arc BC = 5π cm + 2π cm = 7π cm

5 0
4 years ago
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