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aksik [14]
4 years ago
8

Titan Mining Corporation has 6.8 million shares of common stock outstanding, 245,000 shares of 4.1 percent preferred stock outst

anding, and 130,000 bonds with a semiannual coupon rate of 5.8 percent outstanding, par value $1,000 each. The common stock currently sells for $68 per share and has a beta of 1.20, the preferred stock has a par value of $100 and currently sells for $88 per share, and the bonds have 17 years to maturity and sell for 106 percent of par. The market risk premium is 7.6 percent, T-bills are yielding 3.6 percent, and the company’s tax rate is 23 percent. a. What is the firm’s market value capital structure?

Business
1 answer:
Arte-miy333 [17]4 years ago
6 0

Answer:

Please see attachment.

Explanation:

Please see attachment.

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0.013 is the annualized rate of occurrence (ARO) for a natural disaster affecting an organization.

Annualised Rate of Occurrence (ARO): An expected frequency of the hazard occurring over the course of a year is known as the Annualised Rate of Occurrence (ARO). ALE is computed using ARO (annualized loss expectancy).

The annualised rate is applicable for a specific amount of time (less than 12 months). It is a mathematical extrapolation of an estimated yearly returns rate. In order to determine it, multiply the monthly change in returns rate by 12 to obtain the annual rate.

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3 0
1 year ago
A subcontractor is responsible for outfitting six satellites that will be used for solar research. Four of the six have been com
BlackZzzverrR [31]

Answer: ∑Tₓ = 201.222

time required to complete the last two units is 201.222 minutes

Explanation:

Given that,

total time required to four units is 600 hours,

Learning curve applied is 75% and from the learning curve coefficient table, total time factor to complete four units at 75% learning curve is 2.946

so

∑Tₙ = T₁ × total time factor

{ ∑Tₙ is total time required to complete all the units which is 600 hrs, T₁ is Time for first unit, total time factor = 2.946 }

we substitute

∑T₄ = ∑T₁ × total time factor

600 = ∑T₁ × 2.946

∑T₁  = 600/2.946

∑T₁  = 203.666 minutes

Now to get the total time required to complete 6 units, we say:

∑T₆ = ∑T₁ × total time factor

Note that total time factor at this point changes;

( from the learning curve coefficient table, total time factor to complete 6 units at 75% learning curve is 3.934)

so we substitute

∑T₆ = 203.666 × 3.934

∑T₆ = 801.222

Now to find how long should it take them to finish the last two units, we say

∑Tₓ = ∑T₆ - ∑T₄

∑Tₓ = 801.222 - 600

∑Tₓ = 201.222

Therefore time required to complete the last two units is 201.222 minutes

5 0
4 years ago
3. What are three purchasing activities in businesses?
zheka24 [161]
Mark me brainiest


Personal Purchases.
Mercantile Purchasing.
Industrial Purchasing.
Institutionalized or government purchasing.
3 0
3 years ago
as discussed in your reading material,the word nature in the "nature versus nurture" argument refers mainly to
slega [8]
<span>As discussed in your reading material,the word nature in the "nature versus nurture" argument refers mainly to genetics.</span>
6 0
3 years ago
Culver Corporation purchased machinery on January 1, 2022, at a cost of $288,000. The estimated useful life of the machinery is
Digiron [165]

Answer:

Instructions are below.

Explanation:

Giving the following information:

Purchasing price= $288,000

Useful life= 4 years

Salvage value= $33,800

First, we will calculate the depreciation expense using the straight-line method:

Annual depreciation= (original cost - salvage value)/estimated life (years)

Annual depreciation= (288,000 - 33,800)/4

Annual depreciation= $63,550

Now, using the double-declining balance:

Annual depreciation= 2*[(book value)/estimated life (years)]

Year 1= 2*63,550= 127,100

Year 2= [(254,200 - 127,100)/4]*2= $63,550

Year 3= [(127,100 - 63,550)/4]*2= $31,775

Year 4= [(63,550 - 31,775)/]*2= $15,887.5

6 0
4 years ago
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