The correct answer is: [D]: "5 (five)" .
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<u>Note</u>: The term of "degree 8" is the term with a variable with
an exponent of "8" ; which in this case is " + 5x⁸ ".
The "coefficient" is "5" (five).
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Answer:
Scale Factor = 2
Step-by-step explanation:
ABC is your original triangle and A'B'C' is the dilation. You know these are similar triangles so only one side has to be used to find the scale factor. AB has a length of 3 and A'B' has a length of 6 so you know the side lengths of A'B'C' are going to be 2 times the size of triangle ABC side lengths. This gives you a scale factor of 2.
6 - p....p = 1.5
6 - 1.5 = 4.5
TRUE...because when u sub in 1.5 for p, the difference is 4.5, which is less then 5.
(30)(420) = 12000 - 600
12600 = 11400...incorrect
FALSE...because the product of 30 and 420 does not equal 600 less then 12000
16.3 + 11.9 < 27
28.2 < 27..incorrect
FALSE...because the sum of 16.3 and 11.9 is greater then 27
Value of 1.2^2=1.44
value of 2^3+17-3*4=8+17-12=13
value of 9^2/3^3= 81/27=3
Answer:
![p=10\sqrt[3]{54}x^2](https://tex.z-dn.net/?f=p%3D10%5Csqrt%5B3%5D%7B54%7Dx%5E2)
Step-by-step explanation:
We are given parallelogram
Since, two opposite sides of any parallelogram are always equal
Let's assume first side =a
second side =b
so, we get
![a=2\sqrt[3]{54}x^2](https://tex.z-dn.net/?f=a%3D2%5Csqrt%5B3%5D%7B54%7Dx%5E2)
![b=3\sqrt[3]{54}x^2](https://tex.z-dn.net/?f=b%3D3%5Csqrt%5B3%5D%7B54%7Dx%5E2)
now, we can find perimeter
perimeter=2a+2b
so, we get
![p=2(2\sqrt[3]{54}x^2)+2(3\sqrt[3]{54}x^2)](https://tex.z-dn.net/?f=p%3D2%282%5Csqrt%5B3%5D%7B54%7Dx%5E2%29%2B2%283%5Csqrt%5B3%5D%7B54%7Dx%5E2%29)
we can simplify it
![p=4\sqrt[3]{54}x^2+6\sqrt[3]{54}x^2](https://tex.z-dn.net/?f=p%3D4%5Csqrt%5B3%5D%7B54%7Dx%5E2%2B6%5Csqrt%5B3%5D%7B54%7Dx%5E2)
................Answer
