All categories

3 years ago

How many different ways can you arrange 10 letters?

Mathematics

1 answer:

Sloan [31]3 years ago

8 0

Multiply all of them together.10*9*8 and so on...
3,628,800 ways !

You might be interested in

Solve the Integral of 1/(1-y2)

Eva8 [605]

−1/(y+1)(y−1) is the answer

5 0

3 years ago

Oxnard Petro Ltd. is buying hurricane insurance for its off-coast oil drilling platform. During the next five years, the probabi

gavmur [86]

Answer:

$406,000,000

Step-by-step explanation:

Given that:

During the next five years;

the probability of total loss of only the above-water superstructure ($330 million) = .35

the probability of total loss of the facility ($830 million) = .35

the probability of no loss = .30

The Expected loss is being calculated by using the summation of both the total loss amount with their corresponding probability of loss

i.e

Expected Loss = Σ ($ 330,000,000 × .35) + ($ 830,000,000 × .35)

Expected Loss = $ 115,500,000 + $ 290,500,000

Expected Loss = $ 406,000,000

7 0

3 years ago

The area of a trapezoid is 60 square inches. One of the bases is 8 inches long. The height is 6 inches long. What is the length

Mashcka [7]

Answer:

12 in

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = $\frac{1}{2}$ h(b₁ + b₂ )

where h is the height and b₁, b₂ the parallel bases

Given h = 6, b₁ = 8 and A = 60 , then

$\frac{1}{2}$ × 6 × (8 + b₂ ) = 60 , that is

3(8 + b₂ ) = 60 ( divide both sides by 3 )

8 + b₂ = 20 ( subtract 8 from both sides )

b₂ = 12

The length of the second base is 12 inches

6 0

3 years ago

PLEASE HELP!!

Montano1993 [528]

Your method is right so u already know how to do it

7 0

4 years ago

A semicircle has the radius of 2 4/5. What is its area? leave your answers in term of π

Ratling [72]

Answer:

$11\dfrac{13}{25}\pi$

Step-by-step explanation:

r = Radius of semicircle = $2\dfrac{4}{5}=\dfrac{24}{5}\ \text{units}$

Area of semicircle is given by

$A=\dfrac{\pi r^2}{2}\\\Rightarrow A=\dfrac{\pi \left(\dfrac{24}{5}\right)^2}{2}\\\Rightarrow A=\dfrac{288}{25}\pi=11\dfrac{13}{25}\pi\ \text{sq. units}$

The area of the semicircle is $11\dfrac{13}{25}\pi\ \text{sq. units}$ .

4 0

3 years ago