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Lapatulllka [165]
4 years ago
6

J. Reexamine the sequence 20, 14, 8, 2, ... from the problem

Mathematics
1 answer:
DENIUS [597]4 years ago
3 0

Answer:

The n th of the given sequence is t_{n} = 26-6 n

Step-by-step explanation:

<u>Step 1</u> :-

Given sequence is 20,14,8,2,.......this sequence in arithmetic progression but this sequence is decreasing sequence.

given first term is 20 and difference isd = second term- first term = 14-20=-6

now the nth term of given sequence is

by using formula t_{n}=a+(n-1)d

t_{n}= 20+(n-1)(-6)

t_{n}= 20-6 n+6

final answer:-

t_{n} = 26-6 n

<u>verification</u>:-

t_{n} = 26-6 n

put n=1 we get first term is 20

put n=2 we get second term is 14

put n=3 we get third term is 8

put n=4 we get fourth term is 2

so the n th term of sequence is

t_{n} = 26-6 n

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What is the solution to the following system? 4x+3y-z=-6 6x-y+3z=12 8x+2y+4z=6
andrew-mc [135]

Answer:

Option B is correct.

Step-by-step explanation:

4x+3y-z= -6     eq(1)

6x-y+3z= 12     eq(2)

8x+2y+4z=6    eq(3)

We need to solve these equations and find the value of x, y and z.

Multiply equation 2 with 3 and then add equation 1 and 2

18x -3y +9z = 36

4x +3y -z = -6

_____________

22x + 8z = 30    eq(3)

Multiply equation 2 with 2 and add with equation 3

12x -2y + 6z = 24

8x +2y +4z = 6

____________

20x + 10 z = 30  eq(4)

Multiply equation 3 with 10 and equation 4 with 8 and then subtract

220x + 80z = 300

160x + 80z = 240

-        -            -

_________________

60x = 60

x= 60/60

x= 1

Putting value of x in equation 3

22x + 8z = 30

22(1) + 8z = 30

8z = 30 - 22

8z = 8

z = 8/8

z=1

Putting value of x and z in equation 1

4(1)+3y-(1)=-6

4 + 3y -1 = -6

3 + 3y = -6

3y = -6 -3

3y = -9

y = -3

so, Option B x=1, y=3 and z=1 is correct

8 0
3 years ago
Read 2 more answers
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