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aivan3 [116]
3 years ago
11

Suppose you have 30CD's. You know that you have 11 more CD's than your friend. Write and solve an equation to find the number of

CD's your friend has.
Mathematics
2 answers:
Serga [27]3 years ago
4 0

Answer:

30 - 11 = 19        19 CD's

Step-by-step explanation:


I am Lyosha [343]3 years ago
4 0

Answer:

30-11=x

x is what the friend has

or you can do x+11=30

x is what ur friend has still.

take the 11 over to the other side.

x=19

ur friend has 19 and you 30

19+11=30

Hope that helps!! :) Brainliest???



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Translate the question into a mathematical expression. The quotient of two and a number times seven
goblinko [34]

Answer:

2n * 7

Step-by-step explanation:

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3 years ago
An author argued that more basketball players have birthdates in the months immediately following July​ 31, because that was the
Lady_Fox [76]

Answer:

There is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same​ frequency.

Step-by-step explanation:

In this case we need to test whether there is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same​ frequency.

A Chi-square test for goodness of fit will be used in this case.

The hypothesis can be defined as:

<em>H₀</em>: The observed frequencies are same as the expected frequencies.

<em>Hₐ</em>: The observed frequencies are not same as the expected frequencies.

The test statistic is given as follows:

 \chi^{2}=\sum{\frac{(O-E)^{2}}{E}}

The values are computed in the table.

The test statistic value is \chi^{2}=128.12.

The degrees of freedom of the test is:

n - 1 = 12 - 1 = 11

Compute the <em>p</em>-value of the test as follows:

p-value < 0.00001

*Use a Chi-square table.

p-value < 0.00001 < α = 0.05.

So, the null hypothesis will be rejected at any significance level.

Thus, there is sufficient evidence to warrant rejection of the claim that professional basketball players are born in different months with the same​ frequency.

6 0
3 years ago
PLEASE HELP<br> -7y = -91 <br> What does y equal
rusak2 [61]

Answer: I think i got it because -7y/-7 = -91/-7 equals 13 so y = 13

Step-by-step explanation:

4 0
3 years ago
2.The number of grams A of a certain radioactive substance present at time, in yearsfrom the present, t is given by the formulaA
professor190 [17]

Answer:

Given that,

The number of grams A of a certain radioactive substance present at time, in years

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A=45e^{-0.0045(t)}

a) To find the initial amount of this substance

At t=0, we get

A=45e^{-0.0045(0)}A=45e^0

We know that e^0=1 ( anything to the power zero is 1)

we get,

A=45

The initial amount of the substance is 45 grams

b)To find thehalf-life of this substance

To find t when the substance becames half the amount.

A=45/2

Substitute this we get,

\frac{45}{2}=45e^{-0.0045(t)}

\frac{1}{2}=e^{-0.0045(t)}

Taking natural logarithm on both sides we get,

\ln (\frac{1}{2})=-0.0045(t)^{}(-1)\ln (\frac{1}{2})=0.0045(t)\ln (\frac{1}{2})^{-1}=0.0045(t)\ln (2)=0.0045(t)0.6931=0.0045(t)t=\frac{0.6931}{0.0045}t=154.02

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c) To find the amount of substance will be present around in 2500 years

Put t=2500

we get,

A=45e^{-0.0045(2500)}A=45e^{-11.25}A=45\times0.000013=0.000585A=0.000585

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4 0
1 year ago
Quiz in genser
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