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aivan3 [116]
3 years ago
11

Suppose you have 30CD's. You know that you have 11 more CD's than your friend. Write and solve an equation to find the number of

CD's your friend has.
Mathematics
2 answers:
Serga [27]3 years ago
4 0

Answer:

30 - 11 = 19        19 CD's

Step-by-step explanation:


I am Lyosha [343]3 years ago
4 0

Answer:

30-11=x

x is what the friend has

or you can do x+11=30

x is what ur friend has still.

take the 11 over to the other side.

x=19

ur friend has 19 and you 30

19+11=30

Hope that helps!! :) Brainliest???



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7 0
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Factor completely m^2 - 5m - 14 show your work
BigorU [14]

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Factor m^2-5m-14

(m-7) (m+2)



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Help math sucks THESE MAKE MY BRAIN DIE​
Flura [38]

Answer:

A ∩ B = {1, 3, 5}

A - B = {2, 4}

Step-by-step explanation:

The given problem regards sets and set notation, a set can simply be defined as a collection of values. One is given the following information:

A = {1, 2, 3, 4, 5}

B = {1, 3, 5, 6, 9}

One is asked to find the following:

A ∩ B,

A - B

1. Solving problem 1

A ∩ B,

The symbol (∩) in set notation refers to the intersection between the two sets. It essentially asks one to find all of the terms that two sets have in common. The given sets (A) and (B) have the values ({1, 3, 5}) in common thus, the following statement can be made,

A ∩ B = {1, 3, 5}

2. Solving problem 2

A - B

Subtracting two sets is essentially taking one set, and removing the values that are shared in common with the other set. Sets (A) and (B) have the following values in common ({1, 3, 5}). Thus, when doing (A - B), one will omit the values ({1, 3, 5}) from set (A).

A - B = {2, 4}

3 0
3 years ago
Construct a​ 99% confidence interval for the population​ mean, mu. Assume the population has a normal distribution. A group of 1
Zarrin [17]

Answer:

99% confidence interval for the population​ mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population​ mean is given by;

         P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean age of selected students = 22.4 years

             s = sample standard deviation = 3.8 years

             n = sample of students = 19

             \mu = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.878 < t_1_8 < 2.878) = 0.99  {As the critical value of t at 18 degree of

                                                freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 2.878) = 0.99

P( -2.878 \times {\frac{s}{\sqrt{n} } } < {\bar X - \mu} < 2.878 \times {\frac{s}{\sqrt{n} } } ) = 0.99

P( \bar X -2.878 \times {\frac{s}{\sqrt{n} } < \mu < \bar X +2.878 \times {\frac{s}{\sqrt{n} } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X -2.878 \times {\frac{s}{\sqrt{n} } , \bar X +2.878 \times {\frac{s}{\sqrt{n} } ]

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Therefore, 99% confidence interval for the population​ mean is [19.891 , 24.909].

6 0
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Vera_Pavlovna [14]

Answer:

There are 801 box seats and 9612 regular seats.

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➙ 12(801)

➙ 9612

There are 9612 regular seats.

6 0
2 years ago
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