<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
6x-2=5x+29
6x-5x-2=29
x-2=29
x=31
Answer:
Fill in the blank with 14
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Step-by-step explanation:
Given
The attached table
Required
Fill in the gap
Since, the table represents a linear function.
The first step is to calculate the slope of the table

Where






The equation of the table is calculated next as:

This becomes


Solve for y


To fill in the blank;
The value of x is 4
So, substitute 4 for x in 


