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3 years ago

Justin calculates the perimeter of a rectangle with a length of 2x-3 and width

Mathematics

2 answers:

Scorpion4ik [409]3 years ago

6 0

Answer:

No, his answer should have been 6x+2

Step-by-step explanation:

The equation for perimeter is 2L+ 2W=P

so 2 (2x-3) + 2 (x+4) = 6x+2

n200080 [17]3 years ago

5 0

Answer:

Step-by-step explanation:

No, because the perimeter of a rectangle is 2(x+y). Justin added the sides. Then he should have multiplied by 2 but he didn't so Justin is incorrect.

Hope this helps plz mark brainliest :D

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Answer:

Step-by-step explanation:

We are given:

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Since cosine is the ratio of the adjacent side over the hypotenuse, this means that the opposite side is (we can ignore negatives for now):

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And since θ is in QIII, sine/cosecant is negative, cosine/secant is negative, and tangent/cotangent is positive.

Cosecant is given by the hypotenuse over the opposite side. Thus:

$\displaystyle \csc(\theta)=\frac{13}{5}$

Since θ is in QIII, cosecant must be negative:

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