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ELEN [110]
2 years ago
12

Suppose the bacteria population in a specimen increases at a rate proportional to the population at each moment. There were 100

bacteria 4 days ago and 100,000 bacteria 2 days ago. How many bacteria will there be by tomorrow
Mathematics
1 answer:
NNADVOKAT [17]2 years ago
7 0

9514 1404 393

Answer:

  about 3,160,000,000

Step-by-step explanation:

"Increases at a rate proportional to population" means the growth is exponential. It can be modeled by the equation ...

  p = ab^t

We can find 'a' and 'b' using the given data points.

  100 = ab^(-4) . . . . . . . population 4 days ago

  100,000 = ab^(-2) . . . population 2 days ago

Dividing the second equation by the first, we find ...

  1000 = b^2

  b = 1000^(1/2)

Substituting for b in the first equation, we have ...

  100 = a(1000^(1/2))^(-4) = a(1000^-2)

  100,000,000 = a

Then the population model is ...

  p = 100,000,000×1000^(t/2)

__

Tomorrow (t=1), the population will be ...

  p = 100,000,000 × 1000^(1/2) ≈ 31.6 × 100,000,000

  p ≈ 3,160,000,000 . . . . . bacteria by tomorrow

_____

<em>Additional comment</em>

We could write this as ...

  p = 10^(8+1.5t)

Then for t=1, this is p = 10^(8+1.5) = 10^0.5 × 10^9 = 3.16×10^9

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Let f(x)=6/5x−1/2. Describe the transformations from the graph of f to the graphs of g(x)=−f(x) and h(x)=f(−x).
aivan3 [116]

Answer:

g(x)=-6/5x+1/2

h(x)=-6/5x-1/2

Step-by-step explanation:

1).   g(x)=−f(x) ?

f(x)=6/5x−1/2

g(x)=−(6/5x−1/2)

<u>g(x)=-6/5x+1/2</u>

2). h(x)=f(−x) ?

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cylindrical-shaped aquarium is to be filled with water for the newly bought salt water fishes. How much salt water is needed if the aquarium has a 2 ft radius of its base and a height of 3 ft?

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V = (3.14) (4) (3)

V = 37.68 ft³

37.68 ft³ of salt water is needed to fill the cylindrical aquarium.

Mr. Lee is buying a spherical water tank for his tomato plantation. How much water could be stored if the water tank has a radius of 2 meters?

Volume = (4/3) πr³

V = (4/3) (3.14) (2)³

V = (4/3) (3.14) (8)

V = (4/3) (25.12)

V = 33.493 m³

Mr. Lee can store 33.493 m³ of water in the spherical tank.

https://brainly.ph/question/15441850

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