Suppose U1 and U2 are i.i.d. Unif(0,1) withU1=0.1 and U2=0.8. Use the "cosine" version of Box-Muller to generate a single Nor(-1
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Answer
given,
mean = 12 Kg
standard deviation = 0.5 Kg
assume the observed statistic is = 11.1
now,
assuming the number of sample = 4
n = 4
Hypothesis test:
H₀ : μ≥ 12
Ha : μ < 12
now,
significant level α = 0.05
z* = -3.60
Test statistics, Z* = -3.60
P-value
P(Z<-3.60) = 0.002 (from z- table)
P- value = 0.002
now,
reject the value of H₀ when P-value < α
0.002 < 0.05
since, it is less P-value < α , we have to reject the null hypothesis