What is the perimeter of square ABCD?

HELP WITH THIS MATH PROBLEM 93. Points

nadya68 [22]

Answers:

4; 20; 3x² - 4x + 3; 52; 17

Step-by-step explanation:

f(-1): replace x in f(x) = x² + 3 with -1: f(-1) = (-1)² + 3 = 4

f(-4) + g(-1) = (-4)² + 3 + 2(-1) + 3 = 16 + 3 - 2 + 3 = 20 (since g(x) = 2X + 3)

3f(x) - 2g(x) = 3[x² +3] - 2[2x + 3} = 3x² + 9 - 4x - 6 = 3x² - 4x + 3

f(g(2)): First, evaluate g(2). It is g(2) = 2(2) + 3 = 7. Next, use this output, 7, as the input to f(x): f(g(x)) = (7)² + 3 = 49 + 3 = 52

g(f(2)): First, evaluate f(x) at x = 2: f(2) = (2)² + 3 = 7. Next, use this 7 as the input to g(x): g(f(2)) = g(7) = 2(7) + 3 = 17

8 0

3 years ago

Read 2 more answers

The expression 6+16k factored using the GCF is what???????

tatiyna

Answer:

2(3 + 8k)

Step-by-step explanation:

given : 6+16k

note that the GCF of 6 and 16 is 2, hence we can factor 2 out of the expression

6+16k

= (2)(3) + (2)(8k)

= 2(3 + 8k)

4 0

3 years ago

PLZ HELP!!!! 20 POINTS!! What is the value of x?

vazorg [7]

Answer:

25

Step-by-step explanation:

X² = 7² + 24²

X² = 49 + 576

X² = 625

X = 25

4 0

2 years ago

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Prism with a length of 2 yd, a widht of 4 yd , and a height of 5yd

lorasvet [3.4K]

Answer:

40 yd

Step-by-step explanation:

Rectangular prism formula:

A = lwh

A = (2)(4)(5)

A = 40

7 0

2 years ago

I need help 6x-2y=10 x-2y=-5 solve by elimination

dem82 [27]

<h3>Explanation</h3>

Given the system of equations.

$\begin{cases} 6x - 2y = 10 \\ x - 2y = - 5 \end{cases}$

Solve the system of equations by eliminating either x-term or y-term. We will eliminate the y-term as it is faster to solve the equation.

To eliminate the y-term, we have to multiply the negative in either the first or second equation so we can get rid of the y-term. I will multiply negative in the second equation.

$\begin{cases} 6x - 2y = 10 \\ - x + 2y = 5 \end{cases}$

There as we can get rid of the y-term by adding both equations.

$(6x - x) + ( - 2y + 2y) = 10 + 5 \\ 5x + 0 = 15 \\ 5x = 15 \\ x = \frac{15}{5} \longrightarrow \frac{ \cancel{15}}{ \cancel{5}} = \frac{3}{1} \\ x = 3$

Hence, the value of x is 3. But we are not finished yet because we need to find the value of y as well. Therefore, we substitute the value of x in any given equations. I will substitute the value of x in the second equation.

$x - 2y = - 5 \\ 3 - 2y = - 5 \\ 3 + 5 = 2y \\ 8 = 2y \\ \frac{8}{2} = y \\ y = \frac{8}{2} \longrightarrow \frac{ \cancel{8}}{ \cancel{2}} = \frac{4}{1} \\ y = 4$

Hence, the value of y is 4. Therefore, we can say that when x = 3, y = 4.

Answer Check by substituting both x and y values in both equations.

First Equation

$6x - 2y = 10 \\ 6(3) - 2(4) = 10 \\ 18 - 8 = 10 \\ 10 = 10 \longrightarrow \sf{true} \: \green{ \checkmark}$

Second Equation

$x - 2y = - 5 \\ 3 - 2(4) = - 5 \\ 3 - 8 = - 5 \\ - 5 = - 5 \longrightarrow \sf{true} \: \green{ \checkmark}$

Hence, both equations are true for x = 3 and y = 4. Therefore, the solution is (3,4)

<h3>Answer</h3>

$\begin{cases} x = 3 \\ y = 4 \end{cases} \\ \sf \underline{Coordinate \: \: Form} \\ (3,4)$

8 0

3 years ago

What is the perimeter of square ABCD?​

What is the perimeter of square ABCD?