((1+4i)/i) +(1+i)/(2+5i)
(((1+4i)*(2+5i)) +((1+i)*<span>i))/(i*(2+5i))
</span>((2 + 8i + 5i +20i²) + (1i + i²) )/ (2i + 5i<span>²)
((2 + 13i -20) + (1i -1))/(2i - 5) where </span>i<span>² = -1</span><span>
((14i - 19) +0)/2i - 5
(14i -19)/(2i - 5) </span>
Answer:
3,6,9,12
Step-by-step explanation:
In this patter each number is 3 numers more than the previos
In a math book??? Need more explanation
Answer:
d(-8)=-8 . it is very easy
A. both the equations are identities , i’m pretty sure
