(-1,6)(2,-6)
slope = (-6 - 6) / (2 - (-1) = -12/3 = -4
y = mx + b
slope(m) = -4
(-1,6)...x = -1 and y = 6
sub and find b, the y int
6 = -4(-1) + b
6 = 4 + b
6 - 4 = b
2 = b
so the equation is : y = -4x + 2 <=== here is one
y - y1 = m(x - x1)
slope(m) = -4
(-1,6)...x1 = -1 and y1 = 6
sub
y - 6 = -4(x - (-1) =
y - 6 = -4(x + 1) <=== here is one
y - y1 = m(x - x1)
slope(m) = -4
(2,- 6)...x1 = 2 and y1 = - 6
sub
y - (-6) = -4(x - 2) =
y + 6 = -4(x - 2) .... here is one, but it is not an answer choice
Answer:
A) 9 photos in each row
B) 14 rows in total
Step-by-step explanation:
Photos of People = 45
Photos of Landscapes = 18
Photos of Pets = 63
Jenny wants to arrange these photos in rows with only one kind of photos in each row and same number of photos in each row. We have to find the greatest possible number of photos in each row. For this we need to find the greatest common factor of 45,18 and 63. This would give us the greatest possible number of photos that can be placed in each row.
By observing the 3 numbers, we can tell that the greatest common factor of these 3 numbers is 9. So, Jenny can place 9 photos in each row.
So,
There will be:
45/9 = 5 rows with photos of people
18/9 = 2 rows of photos of landscapes
63/9 = 7 rows of photos of pets
So, total number of rows would be = 5 + 2 + 7 = 14 rows
The U.S wanted to be isolationists
it did not enter the war untill the japanese bombed Pearl Harbor
Answer:
1
Step-by-step explanation:
Answer:
independent: day number; dependent: hours of daylight
d(t) = 12.133 +2.883sin(2π(t-80)/365.25)
1.79 fewer hours on Feb 10
Step-by-step explanation:
a) The independent variable is the day number of the year (t), and the dependent variable is daylight hours (d).
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b) The average value of the sinusoidal function for daylight hours is given as 12 hours, 8 minutes, about 12.133 hours. The amplitude of the function is given as 2 hours 53 minutes, about 2.883 hours. Without too much error, we can assume the year length is 365.25 days, so that is the period of the function,
March 21 is day 80 of the year, so that will be the horizontal offset of the function. Putting these values into the form ...
d(t) = (average value) +(amplitude)sin(2π/(period)·(t -offset days))
d(t) = 12.133 +2.883sin(2π(t-80)/365.25)
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c) d(41) = 10.34, so February 10 will have ...
12.13 -10.34 = 1.79
hours less daylight.
