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3 years ago

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Niacin is particularly important for men over 50 since it helps them to maintain healthy blood cholesterol levels. A researcher

randomly selects 10 men over 50 years old and ascertains whether or not each individual's level of niacin in his bloodstream is high, average, or low. Does this constitute a binomial experiment?

1 answer:

Aleks [24]3 years ago

3 0

Answer:

The experiment conducted by the researcher does not constitute a binomial experiment.

Step-by-step explanation:

A researcher wants to determine the level of Niacin in men over the age of 50 years.

In any particular man, the level of Niacin is either high, average or low.

This implies that for every sample there are three different outcomes.

The experiment performed by the researcher is not a Binomial experiment.

In a Binomial experiment, there are <em>n</em> independent and repeated trials.

Each trial has only two outcomes: Success (S) or failure (F).

And each outcome has the same probability of occurrence.

Thus, the experiment conducted by the researcher does not constitute a binomial experiment.

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1.) You go skiing on one route with an equation = 2 + 4 and then

CaHeK987 [17]

The best information that describes your routes is the second route was steeper than your first, and the second route was higher up the mountain.

<h3>What is the slope of a linear equation?</h3>

The slope of a linear equation is the change in the rise over the run. So, the slope of a linear equation shows that the larger the slope, the steeper the line becomes.

From the given information:

y = 2x + 4 --- (1)

y = 4x + 1 --- (2)

Using the slope-intercept formula:

y = mx + b

m = slope
b = y-intercept

From the first equation, the slope is 2 and in the second equation, the slope is 4.

Therefore, we can conclude that the second route was steeper than your first, and the second route was higher up the mountain.

Learn more about the slope of a linear equation here:

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2 years ago

A company charting its profits notices that the relationship between the number of units sold, x, and the profit, P, is linear.

scoundrel [369]

Answer:

P(x) = 58x - 8,500

Step-by-step explanation:

The profit function can be modeled based on the two given points of format (P, x) that are ($1360, 170) and ($4260, 220). The slope of the function is:

$m=\frac{4,260-1,360}{220-170}\\ m=58$

Applying the general form of a linear equation, the profit function is:

$P-P_0 = m*(x-x_0)\\P - 1,360=58*(x-170)\\P(x) = 58x -8,500$

The profit as a function of units sold is P(x) = 58x - 8,500.

3 0

4 years ago

The Environmental Protection Agency records data on the fuel economy of many different makes of cars. Data on the mileage of 20

artcher [175]

Answer:

A) 8.5 miles per gallon

Step-by-step explanation:

Given

$x = \{12\ 13\ 15\ 16\ 16\ 17\ 18\ 18\ 19\ 19\ 20\ 20\ 22\ 23\ 24\ 26\ 26\ 27\ 27\ 29\}$

$n = 20$

Required

The IQR

This is calculated as:

$IQR = Q_3 - Q_1$

Calculate $Q_1$

$Q_1 = \frac{1}{4}(n + 1)th$

$Q_1 = \frac{1}{4}(20 + 1)th$

$Q_1 = \frac{1}{4}(21)th$

Remove bracket

$Q_1 = 5.25th$

This means that:

$Q_1$ is the mean of 5th and 6th item

From the given data:

$5th \to 16$

$6th \to 17$

So, we have:

$Q_1 = \frac{1}{2}(16 + 17)$

$Q_1 = \frac{1}{2}(33)$

$Q_1 = 16.5$

$Q_1 = 16.25$

Calculate $Q_3$

$Q_3 = \frac{3}{4}(n + 1)th$

$Q_3 = \frac{3}{4}(20 + 1)th$

$Q_3 = \frac{3}{4}(21)th$

Remove bracket

$Q_3 = 15.75th$

This means that:

$Q_3$ is the mean of 15th and 16th item

From the data:

$15th \to 24$

$16th \to 26$

So:

$Q_3 = \frac{1}{2}(24 + 26)$

$Q_3 = \frac{1}{2}(50)$

$Q_3 = 25$

Recall that:

$IQR = Q_3 - Q_1$

$IQR = 25 -16.5$

$IQR = 8.5$

7 0

3 years ago

Please help me please help help me help please

notsponge [240]

Answer:

An equation of a line is written in the form y=mx+b. ”m” is the slope and ”b” is the y-intercept. So, substituting the values, the equation is y=-4x+1.

:)

7 0

3 years ago

About 10% of people in the United States are left handed. Suppose we take a sample of 120 U.S. Residents, and let X = the number

olganol [36]

Answer:

1) $E(X) = np = 120*0.1 =12$

$SD(X) = \sqrt{np(1-p)}= \sqrt{120*0.1*(1-0.1)} =3.286$

For this case we can interpret that the expected variation around the mean is about 3.3 people approximated

2) $P(X\geq 16)$

And we can use the normal approximation given by:

$X \sim N(12, \sigma =3.286)$

And we can use the z score formula given by:

$z = \frac{X -\mu}{\sigma}$

And if we find the z score for 16 we got:

$z = \frac{16-12}{3.286}= 1.217$

And we can find this probability using the normal standard distribution or excel and we got:

$P(Z>1.217) = 0.112$

3) For this case we can conclude that the probability to find 16 or more individuals left handed in a sample of 120 is about 0.112 or 11.2%

Step-by-step explanation:

Let X represent the random variable for the number of residents who are left handed

And for this case we can model this variable with this distirbution:

$X\sim Binom(n= 120 , p =0.1)$

Part 1

The mean is given by:

$E(X) = np = 120*0.1 =12$

And the deviation would be:

$SD(X) = \sqrt{np(1-p)}= \sqrt{120*0.1*(1-0.1)} =3.286$

For this case we can interpret that the expected variation around the mean is about 3.3 people approximated

Part 2

We want to calculate this probability:

$P(X\geq 16)$

And we can use the normal approximation given by:

$X \sim N(12, \sigma =3.286)$

And we can use the z score formula given by:

$z = \frac{X -\mu}{\sigma}$

And if we find the z score for 16 we got:

$z = \frac{16-12}{3.286}= 1.217$

And we can find this probability using the normal standard distribution or excel and we got:

$P(Z>1.217) = 0.112$

Part 3

For this case we can conclude that the probability to find 16 or more individuals left handed in a sample of 120 is about 0.112 or 11.2%

7 0

3 years ago