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Citrus2011 [14]
3 years ago
11

Please help me please help help me help please

Mathematics
1 answer:
notsponge [240]3 years ago
7 0

Answer:

An equation of a line is written in the form y=mx+b. ”m” is the slope and ”b” is the y-intercept. So, substituting the values, the equation is y=-4x+1.

:)

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HURRY HELP PLS‼️‼️‼️
Brums [2.3K]

Answer:

Step-by-step explanation:

To solve this problem you need the function

 

h(t) = -16t2 + v0t + h0

where t = time

v0 is the initial velocity, which in our case is 0

h0 = initial height, which in our case is 256

h(t) = 0 since we want to know when the ball will hit the ground.

 

0 = -16 t2 + 256

 

And we can solve for t

 

If we rearrange the terms we see that this is a difference of 2 squares

0 = 256 - 16t2

 

0 = (16-4t)(16+4t)

Setting each factor = 0

16-4t=0       16+4t=4

t = 4             t = -4

 

The second solution is discarded as time cannot be negative.

 

So the ball will hit the ground in 4 seconds.

6 0
2 years ago
16
enot [183]

Answer:

D) 4.01 miles

Step-by-step explanation:

2.87 miles from Monday + 1.14 miles =4.01 ran on Tuesday

5 0
3 years ago
Read 2 more answers
The variables x and y have a proportional relationship, and y=5/6 when x=3/4. Which equation represents this relationship?
seropon [69]

Answer:

y = 1 1/9

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4 0
2 years ago
The area of a rectangle is 30 square root 3750 square inches, and the length is 3 square root 250 inches what is the width of th
Ann [662]

Answer:

width=10\sqrt{15}\ in

Step-by-step explanation:

-A rectangle's area is given by:

A=lw\\\\l=length\\w=width

Given A=30\sqrt{3750} and l=3\sqrt{250}, we substitute in the formula to solve for the width as follows:

A=lw\\\\30\sqrt{3750}=3\sqrt{250}\times w\\\\w=\frac{30\sqrt{3750}}{3\sqrt{250}}\\\\w=10\frac{\sqrt{3750}}{\sqrt{250}}\\\\=10\times \sqrt{\frac{3750}{250}}\\\\=10\sqrt{15}\ in

Hence , the rectangle's width is 10\sqrt{15}\ in

6 0
3 years ago
Help me please!!!!!!!?
vovikov84 [41]
It is c.it is actually 1.548 but you round it so....
5 0
3 years ago
Read 2 more answers
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