Find the first three iterates of the function f(z) = z^2+c with c=1-3i and an initial value of z0=i
1 answer:
You might be interested in
Answer:
x=2.17
Step-by-step explanation:
+18x+81=-4
-81 -81
+18x= -85
/18 /18
= -4.7
=
x= 2.17
I hope this helps :) (if it does, brainliest, please??)
<h2>Greetings!</h2><h3>Firstly, the slope is found by rearranging the formula:</h3>
<h2>Hope this helps!</h2>
3y = 4x + 39
y = +
When x is 0, y = 0(x) + , so the y intercept is
So can be rearranged to
, so the slope would be
.
<h2>Hope this helps!</h2>