Find the first three iterates of the function f(z) = z^2+c with c=1-3i and an initial value of z0=i
1 answer:
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Answer:
Step-by-step explanation:
<u>Given expression:</u>
<h3>= 2(4f + 2g)</h3>Distribute 2 to both terms.
<h3>= 8f + 4g</h3>We can also split 8f into 4f and 4f.
<h3>= 4f + 4f + 4g</h3>If we take 4 common
= 4(f + f + g)
<h3>= 4(2f + g)</h3>Answer:
Step-by-step explanation:
Factor top and bottom.
The numerator is a difference of two squares, and the denominator is a quadratic.
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If x does not equal -1 and does not equal 4, we can cancel the common factors in italics to give
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Answer:
BCA
Step-by-step explanation:
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