Let's solve the equation:
9x+27 = 9(x+2)+9 ← Distribute 9 to the x and 2
9x+27 = 9x+18+9 ← Combine like terms
9x+27 = 9x + 27 ← Subtract 27 from both sides
9x = 9x
Infinitely many solutions would be correct because no matter what x is, it will always equal each other the both sides of the equation because it is 9 times x on both sides.
Answer:
out of 10?
Step-by-step explanation:
probably a 7-8? maybe 9?

The final result is: C) x(x - 8)(x + 8).