A square ABCD has the vertices A(n, n), B(n, -n), C(-n, -n), and D(-n, n). Which vertex is in Quadrant III?

Mathematics

2 answers:

andreyandreev [35.5K]3 years ago

8 0

The answer is C because it's two negatives. Hope that helped

svet-max [94.6K]3 years ago

4 0

Answer:

C(-n, -n) Option C

Step-by-step explanation:

Here given that four coordinates:

A(n, n)

B(n, -n)

C(-n, -n )

D(-n, n)

Here we need to find the coordinate that is lie on the third quadrant.

The third quadrant is where both the coordinate and the coordinate of a point are negative.

In other words, x and y values both the negative.

For example: (-x, -y)

In given coordinates vertex C have x and y values both are negative.

So, Option third is correct.

C(-n, -n) is correct.

You might be interested in

What are the measures of the missing angles x°, y° of a regular triangle if one angle measure equals 60°?

MArishka [77]

Answer:

So each interior angle measurement of the regular triangle is 60 degrees.

Step-by-step explanation:

If the triangle is regular, this means all the side measurements are congruent to each other and that all the angle measurements are congruent to each other.

If the sum of the angles in a triangle is 180 degrees and you know they are each the same then you could either solve x+x+x=180 or know we are just dealings with an equiangular triangle in which all angles have measurement 60 degrees.

If need more convincing, let's actually solve:

x+x+x=180

3x=180

x=180/3

x=60

So each interior angle measurement of the regular triangle is 60 degrees.

3 0

3 years ago

Which graph shows a negative acceleration?

Kitty [74]

Answer:

Third