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3 years ago

A square ABCD has the vertices A(n, n), B(n, -n), C(-n, -n), and D(-n, n). Which vertex is in Quadrant III?

Mathematics

2 answers:

andreyandreev [35.5K]3 years ago

8 0

The answer is C because it's two negatives. Hope that helped

svet-max [94.6K]3 years ago

4 0

Answer:

C(-n, -n) Option C

Step-by-step explanation:

Here given that four coordinates:

A(n, n)

B(n, -n)

C(-n, -n )

D(-n, n)

Here we need to find the coordinate that is lie on the third quadrant.

The third quadrant is where both the coordinate and the coordinate of a point are negative.

In other words, x and y values both the negative.

For example: (-x, -y)

In given coordinates vertex C have x and y values both are negative.

So, Option third is correct.

C(-n, -n) is correct.

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From the value obtained we see that $p-value > \alpha$ hence

The decision rule is

Fail to reject the null hypothesis

The conclusion is

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