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3 years ago

A square ABCD has the vertices A(n, n), B(n, -n), C(-n, -n), and D(-n, n). Which vertex is in Quadrant III?

Mathematics

2 answers:

andreyandreev [35.5K]3 years ago

8 0

The answer is C because it's two negatives. Hope that helped

svet-max [94.6K]3 years ago

4 0

Answer:

C(-n, -n) Option C

Step-by-step explanation:

Here given that four coordinates:

A(n, n)

B(n, -n)

C(-n, -n )

D(-n, n)

Here we need to find the coordinate that is lie on the third quadrant.

The third quadrant is where both the coordinate and the coordinate of a point are negative.

In other words, x and y values both the negative.

For example: (-x, -y)

In given coordinates vertex C have x and y values both are negative.

So, Option third is correct.

C(-n, -n) is correct.

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3 years ago

triangle is placed in a semicircle with a radius of 8cm, as shown below. Find the area of the shaded region. Use the value 3.14

zhuklara [117]

Answer:

Area of shaded region is $36.48 \ cm^2$ .

Step-by-step explanation:

We have drawn the diagram for your reference.

Given:

radius = 8 cm

Diameter is 2 times radius.

Diameter = $2\times 8 =16 \ cm$

We need to find the Area of shaded region.

Solution:

First we will find the Area of Semicircle.

Now we know that Area of semicircle is half times π times square of radius.

framing in equation for we get;

Area of Semicircle = $\frac{1}{2} \times \pi \times r^2 = \frac{1}{2} \times \pi \times 8^2=100.48\ cm^2$

Now we will find the Area of Triangle.

Now base diameter of the semicircle and height is radius of the circle.

We know that Area of triangle is half times base times height.

framing in equation form we get;

Area of triangle = $\frac{1}{2} \times 16 \times 8 = 64 \ cm^2$

Now Area of the shaded region can be calculated by subtracting Area of triangle from Area of semicircle.

framing in equation form we get;

Area of the shaded region = $100.48 - 64 = 36.48 \ cm^2$

Hence Area of shaded region is $36.48 \ cm^2$ .

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3 years ago