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bonufazy [111]
2 years ago
13

Tameka signs up for membership at a rock climbing gym. She pays a

Mathematics
1 answer:
SSSSS [86.1K]2 years ago
8 0

Answer and Step-by-step explanation:

In the equation y = 25x + 100, the format of y = mx + b is being used. This is a very commonly used base for equations in math, especially when it comes to graphing.

In the equation, the m stands for the slope in the equation, and the b stands for the y intercept. Slope can also be found by taking the rise/run of a graph.

So, the slope of this line is 25, and the y-intercept 100.

I have also included the this equation on a graph as well.

I hope that this helps.

You might be interested in
Why is 743 a prime number
bonufazy [111]
743 is a prime number because it has no other positive divisors besides one and itself.
7 0
3 years ago
An interior automotive supplier places several electrical wires in a harness.Apull test measures the force required to pull spli
oksano4ka [1.4K]

Answer:

a) For this case we can use the following R code to construct the qq plot

> data<-c(28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4)

# The above line is in order to store the data in a vector

> qqnorm(data, pch = 1, frame = FALSE)

# The line above is in order to calculate the quantiles from the data assumin Normal distribution

> qqline(data, col = "steelblue", lwd = 2)

# The line above is in order to put a line for the theoretical dsitribution

The result is on the figure attached.

b) For this case as we can see on the figure attached the calculated quantiles are not far from the theorical quantiles given byt the straaigth blue line so then we can conclude that the distribution seems to be normal.

Step-by-step explanation:

For this case we have the following data:

28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4

The quantile-quantile or q-q plot is a graphical procedure in order to check the validity of a distributional assumption for a data set. We just need to calculate "the theoretically expected value for each data point based on the distribution in question".

If the values are asusted to the assumed distribution, we will see that "the points on the q-q plot will fall approximately on a straight line"

For this case our distribution assumed is normal.

Part a

For this case we can use the following R code to construct the qq plot

> data<-c(28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4)

# The above line is in order to store the data in a vector

> qqnorm(data, pch = 1, frame = FALSE)

# The line above is in order to calculate the quantiles from the data assuming Normal distribution (0,1)

> qqline(data, col = "steelblue", lwd = 2)

# The line above is in order to put a line for the theoretical distribution

The result is on the figure attached.

Part b

For this case as we can see on the figure attached the calculated quantiles are not far from the theorical quantiles given byt the straaigth blue line so then we can conclude that the distribution seems to be normal.

4 0
3 years ago
The function g(x) = x2 is transformed to obtain function h:
Rudik [331]

Answer:

Option C

The graph of g is vertically shifted 5 units down

4 0
3 years ago
2a + 3b = 5<br> b = a - 5
Lunna [17]
<h2>1st Equation:</h2>

Answer for A:

a =  \frac{5 - 3b}{2}

Answer for B:

b =  \frac{5 - 2b}{3}

<h2>2nd Equation:</h2>

Answer:

a = b + 5

<u>hope it helps</u><u>.</u>

5 0
2 years ago
Mike and Beatrice purchase a house for $200,000. If the equation V = 200,000(1.03)x represents the value of the house after x ye
notsponge [240]
X=((log(225000/200000)/log(1.03))
X=log(225,000÷200,000)÷log(1.03)
X=3.98 years
6 0
3 years ago
Read 2 more answers
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