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3 years ago

7

A Sweet Potato Casserole recipe serves 6 people and calls for 1/4 cup of brown sugar. At this rate, how much brown sugar is need

ed to make a casserole that will serve 27 people? (UNIT RATES QUESTION NEED ANSWER ASAP)

1 answer:

d1i1m1o1n [39]3 years ago

4 0

Answer: I got 4/9

Explanation:

1/4 divided by 6 to find the unit rate of the sugar needed for each serving which is 1/24. Then, you times that fraction by 27 because to find the amount of sugar for the 27 people which is 4/9.

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Lexi picked 2 7/10 pounds of strawberries. That afternoon, Lexi’s sister ate 7/8 of the strawberries. How many pounds of strawbe

gavmur [86]

3 $\frac{3}{35}$ pound of strawberry

Step-by-step explanation:

Given parameters:

Pounds of strawberry picked by Lexi =2 $\frac{7}{10}$

Pounds of strawberry eaten by Lexi sister = $\frac{7}{8}$

Unknown:

Pound of strawberry Lexi's sister ate = ?

Solution:

This is a fraction word problem.

Let pound of strawberry eaten by Lexi's sister = K

We can establish that:

Pound of strawberry eaten by Lexi sister x K = Pound of strawberry picked by Lexi

Mathematically we have:

$\frac{7}{8}$ x K = 2 $\frac{7}{10}$

Learn more:

fractions brainly.com/question/1757979

#learnwithBrainly

K = $\frac{27 x 8}{10 x 7}$ = $\frac{216}{70}$

K = 3 $\frac{3}{35}$ pound of strawberry

8 0

3 years ago

Evealute the expression when m= -2 m^2+9m+3

Volgvan

Step-by-step explanation:

m=-2

m^2+9m+3

substitute-2 in m

-2^2+9(-2)+3

= -19

8 0

2 years ago

Jerry has a miniature model of a boat. He knows that the boat is 3 3/4 inches wide and 5 1/2 inches long. What is the actual len

FromTheMoon [43]

Width of the miniature model = $3\frac{3}{4}$ inches

Length of the miniature model = $5\frac{1}{2}$ inches

The actual width of the boat = 15 feet

Let us find the actual length of the boat.

Write it in a proportion form.

width of model : length of model : : width of actual : length of actual

$$\Rightarrow 3\frac{3}{4}:5\frac{1}{2}::15:x$

$$\Rightarrow\frac{15}{4}:\frac{11}{2}::15:x$

$$\Rightarrow\frac{\frac{15}{4}}{\frac{11}{2}} =\frac{15}{x}$

Do cross multiplication.

$$\Rightarrow{\frac{15}{4}x =15\times\frac{11}{2}$

$$\Rightarrow{\frac{15}{4}x =\frac{165}{2}$

$$\Rightarrow x =\frac{165}{2}\times{\frac{4}{15}$

⇒ x = 22

Hence the actual length of the boat is 22 feet.

6 0

3 years ago

Please help me <br> thank you

lilavasa [31]

Use the Pythagorean theorem. We have legs with lengths of 15 and 20 miles, now let's solve for the hypotenuse.

$a=15$
$b=20$
$c=?$

$a^2+b^2=c^2$
$15^2+20^2=c^2$
$c^2=400+225=625$
$c=25$

Your answer is 25 miles. Hope this helps! :)

7 0

3 years ago

What is the following product? (2 square root 7+3 square root 6)(5 square root 2+4 square root 3)

Xelga [282]

$(2\sqrt7+3\sqrt6)(5\sqrt2+4\sqrt3)\qquad\text{use distributive property}\\\\=(2\sqrt7)(5\sqrt2)+(2\sqrt7)(4\sqrt3)+(3\sqrt6)(5\sqrt2)+(3\sqrt6)(4\sqrt3)\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt{12}+12\sqrt{18}\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt{4\cdot3}+12\sqrt{9\cdot2}\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt4\cdot\sqrt3+12\sqrt9\cdot\sqrt2\\\\=10\sqrt{14}+8\sqrt{21}+(15)(2)\sqrt3+(12)(3)\sqrt2\\\\=\boxed{10\sqrt{14}+8\sqrt{21}+30\sqrt3+36\sqrt2}$

5 0

3 years ago

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