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Lilit [14]
3 years ago
7

Is the square of a complex number always a real number? Explain how, please I would like to finish this tonight.

Mathematics
2 answers:
Artemon [7]3 years ago
7 0

Answer:

<em>The absolute square of a complex number is calculated by multiplying it by its complex conjugate. This give the magnitude squared of the complex number. The absolute square is </em><em>A</em><em>l</em><em>w</em><em>a</em><em>y</em><em>s</em><em> </em><em>R</em><em>e</em><em>a</em><em>l</em><em>. We will use complex exponentials all the time.</em>

seraphim [82]3 years ago
7 0

Answer:

Step-by-step explanation:

I don't thing it is very often unless it is of the form

5i

When you square that, you get a real number (5i)^2 = - 25

On the other hand when you have a binomial like

3 + 2i

and you square that, the result is still a complex number.

(3+2i)(3+2i) = 9 + 6i + 6i + 4i^2 = 5 + 12i

You might be interested in
The system of linear equations 5x+2y = 3 and x+y = -1 is graphed below.What is the solution to the system of equations?
Kazeer [188]

Answer:

<h2>C. (3, -4)</h2>

Step-by-step explanation:

If the system of linear equations is graphed, then the solution is the intersection of lines.

Read it from the graph (look at the picture).

7 0
3 years ago
Please help me its about solving system by substitution
Andrew [12]

Answer:

(-3, 4)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = -x + 1

2x + 3y = 6

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                    2x + 3(-x + 1) = 6
  2. Distribute 3:                         2x - 3x + 3 = 6
  3. Combine like terms:           -x + 3 = 6
  4. Isolate <em>x</em> terms:                   -x = 3
  5. Isolate <em>x</em>:                              x = -3

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define equation:                     y = -x + 1
  2. Substitute in <em>x</em>:                        y = -(-3) + 1
  3. Simplify:                                   y = 3 + 1
  4. Add:                                         y = 4
6 0
3 years ago
3x−2y=−2 6x−2y=10 solve by elimination
Anvisha [2.4K]

Answer:

x=4 y=7

Step-by-step explanation:

When multiplying 3x by -2, you get -6x. -6x and 6x cross out. You're left with -2y=-2 and -2y=10.

3 0
3 years ago
Simplify 3(8x+2y)<br> A. 30x+y<br> B. 24x+2y<br> C. 24x+6y<br> D. 30xy
Naddika [18.5K]

Answer:

The choose C. 24x+6y

Step-by-step explanation:

3(8x + 2y)  = 24x + 6y

I hope I helped you^_^

4 0
3 years ago
The calibration of a scale is to be checked by weighing a 13 kg test specimen 25 times. Suppose that the results of different we
Natali5045456 [20]

Solution :

a).

Given : Number of times, n = 25

            Sigma, σ = 0.200 kg

            Weight, μ = 13 kg

Therefore the hypothesis should be tested are :

$H_0 : \mu = 13 $

$H_a : \mu \neq 13$

b). When the value of $\overline x = 12.84$

 Test statics :

   $Z=\frac{(\overline x - \mu)}{\frac{\sigma}{\sqrt n}} $

  $Z=\frac{(14.82-13)}{\frac{0.2}{\sqrt {25}}} $

          $=\frac{1.82}{0.04}$

          = 45.5  

P-value = 2 x P(Z > 45.5)

            = 2 x 1 -P (Z < 45.5) = 0

Reject the null hypothesis if P value  < α = 0.01 level of significance.

So reject the null hypothesis.

Therefore, we conclude that the true mean measured weight differs from 13 kg.

3 0
3 years ago
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