Susan is making 8 casseroles. She uses 9 cans of beans. Each can is 16 oz. If she divides the beans equally among casseroles? Sh
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The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%
<h3>What is Probability ?</h3>Probability is defined as the likeliness of an event to happen.
Let X be a random variable that shows the term "freshman 15" that claims that students typically gain 15lb during their freshman year at college.
It is given that
X follows is a normal distribution with a mean of 2.1 lb (μ) and a standard deviation (σ) of 10.8 lb.
Population Mean (μ) = 2.1
Population Standard Deviation (σ) = 10.8
We need to compute Pr(X≥15). The corresponding z-value needed to be computed is:
Then the probability is given as
Pr(X≥15)=0.1162. (11.6%)
The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%
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Answer:
Step-by-step explanation:
To solve this problem you must apply the proccedure shown below;
- Make the equation equal to zero:
-Add 49 at both sides:
- Now, you must take the square root of both sides of the equation, then you obtain the following roots:
- Then you have: