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Alecsey [184]
2 years ago
15

What exactly is a root of a logarithmic function again?

Mathematics
1 answer:
Evgen [1.6K]2 years ago
4 0

Answer:

Root, in mathematics, a solution to an equation, usually expressed as a number or an algebraic formula.

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Find the smallest no......<br>only genius <br><br>1 .245, 45 ,67, 2​
Vlad [161]

Answer:

.245

Step-by-step explanation:

brainliest pls thanks bro

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3 years ago
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If y = kx, what is the value of k if y = 20 and x = 0.4? A) 5 B) 8 C) 9.6 D) 50
Margaret [11]
Answer: D, 50
y = kx          <span>y = 20 and x = 0.4
</span>
What you will do: You will plug in your y and your x.
Your equation should look like: 20=k(0.4)
Next: What you will do is divide each side of your equal sign by 0.4 so you will get your k alone.
You would get: k=50

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7 0
3 years ago
Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different
N76 [4]

Answer:

(a)  As time increases, the amount of water in the pool increases.

     11 gallons per minute

(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

Choose 2 ordered pairs from the table:

\textsf{let}\:(x_1,y_1)=(8, 153)

\textsf{let}\:(x_2,y_2)=(12,197)

Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

y-y_1=m(x-x_1)

\implies y-153=11(x-8)

\implies y-153=11x-88

\implies y=11x-88+153

\implies y=11x+65

When Ann had added no water, x = 0.  Therefore,

y=11(0)+65

y=65

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

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2 years ago
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Trey has plastic cubes stored in a box that measures
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Your answer is D.160
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I got this question wrong. I have no idea how to do it. thank you!
ruslelena [56]
Area of aqua: A = bh/2 = (13.4cm) (4cm)/2 = 26.8cm2

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