How do I solve question 13 and 14?

Oceanside Bike Rental Shop charges a 16 dollar

Elden [556K]

Answer: she rented the bike for 5 hours

Step-by-step explanation:

51 - 16 = 35

35/ 7 = 5

7 0

3 years ago

Read 2 more answers

What is the solution to 4n-6=10n?

Trava [24]

First get n's by them selves
-6 = 10n -4n (remember to always change sign when crossing the equals sign.

-6 = 6n ( subtract and take sign of the larger) ( then divide both sides by 6 to solve for n)
-1 = n
hope this helps

5 0

3 years ago

There are 364 students who are enrolled in an introductory biology course. If there are five boys to every eight girls, how many

Butoxors [25]

Answer:

The number of boys in the course will be = 140

Step-by-step explanation:

Given:

Total number of students enrolled in an introductory biology course = 364

There are 5 boys to every 8 girls in the course.

To find how many boys are in the course.

Solution:

Since, there are 5 boys to every 8 girls in the course.

So, ratio of boys to girls enrolled in the course = 5 : 8

Let the number of boys in the course be = $5x$

Then number of girls in the course will be = $8x$

Total number of students would be given as:

⇒ <em>Number of boys + Number of girls</em>

⇒ $5x+8x$

⇒ $13x$

Total number of students given = 364.

Thus, we have:

$13x=364$

solving for $x$

Dividing both sides by 13.

$\frac{13x}{13}=\frac{364}{13}$

∴ $x=28$

So, number of boys in the course will be = $5\times 28$ = 140

5 0

4 years ago

a caterer received an order to prepare 120 servings of salad for a banquet. Each serving will weigh 4 ounces. so far the caterer

Ugo [173]

To easier digest this question, we can multiply the 120 servings by 4 ounces to make it into a common unit of measurement. This way, we can compare ounces with ounces instead of ounces to servings.
We then have 480 servings, and the poor caterer only has 60 ounces. We can put that into a fraction, 60/480. From here, things get slightly easier. All we have to do is make it into a fraction we can digest, which would be 1/8. We can turn that fraction into a decimal by simply dividing. We have 0.125.
Since we are changing from a decimal into a percent, we have to move the decimal point two places to the right. We have out final answer of 12.5%.

6 0

3 years ago

Ignoring those who said they weren't sure, there were 297 men asked, and 183 said yes, they had driven a car when they probably

USPshnik [31]

Answer:

$z=\frac{0.616-0.5}{\sqrt{\frac{0.5(1-0.5)}{297}}}=3.998$

$p_v =2*P(z>3.998)=0.0000639$

With the most common significance levels used $\alpha= 0.1, 0.05, 0.01$ we see that the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can say that the true proportion is significantly higher than 0.5

Step-by-step explanation:

Information given

n=297 represent the random sample of male taken

X=183 represent the men who said yes, they had driven a car when they probably had too much alcohol

$\hat p=\frac{183}{297}=0.616$ estimated proportion of men who said yes, they had driven a car when they probably had too much alcohol

$p_o=0.5$ is the value that we want to test

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Hypothesis to test

We need to conduct a hypothesis in order to test the claim that the majority of men in the population (that is, more than half) would say that they had driven a car when they probably had too much alcohol, and the system of hypothesis are:

Null hypothesis: $p\leq 0.5$

Alternative hypothesis: $p > 0.5$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

After replace we got:

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.616-0.5}{\sqrt{\frac{0.5(1-0.5)}{297}}}=3.998$

Decision

We have a right tailed test so then the p value would be:

$p_v =2*P(z>3.998)=0.0000639$

With the most common significance levels used $\alpha= 0.1, 0.05, 0.01$ we see that the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can say that the true proportion is significantly higher than 0.5

7 0

3 years ago