SOLUTION:
A normal distribution would model this situation because the distribution is approximately symmetrical, thus the mean, median and mode are approximately the same and the population size is large ( greater than 30).
It will become 61
because anything above 0.5 rounds up
Answer:
20.43% probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Graduated with honors:
98 students graduated with honors. Of those, 79 had at least one parent graduating from college. So 98 - 79 = 19 did not.
Of 300 students, 207 had one or both parents graduate from college. So 300 - 207 = 93 did not have at least one parent graduating.
Find the probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.
Of the 93 with no graduated parent, 19 earned honors
19/93 = 0.2043
20.43% probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.
Answer:
c=18
Step-by-step explanation:
2(2)+3y=13
4+3y=13
3y=9
y=3
The answer is B
