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Wewaii [24]
3 years ago
9

I need help with this math questions can anyone help Thanks. Can u help me on #1 and#2

Mathematics
1 answer:
Fynjy0 [20]3 years ago
4 0
1.
yes
x is number of group acts
y is number of indivual acts


2. I would eliminate x by multiplying 2nd equation by -3 then adding

12x+6y=120
<u>-12x-3y=-90 +
</u>0x+3y=30

3y=30
divide by 3
y=10

sub
4x+y=30
4x+10=30
4x=20
divide 4
x=5

each group act takes 5 mins and each individual takes 10 minutes
<u /> 

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The weight in pounds of a baby in the first six months of life can be modeled by the
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14.5

Step-by-step explanation:

You would plug 5 into the equation for m and have w = 1.5 (5) + 7

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For a class trip, a total of 116 ticket need to be purchased. The cost of an adult ticket is $17000. The cost of a child ticket
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Emily is 2 years older than Alysson. The product of their age is 440. How old are they?
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Brainliest?
5 0
2 years ago
two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe
sveta [45]

Applying the required <em>rule </em>or <em>theorem</em>, it can be concluded that the second biker is <u>farther</u> from the <em>parking lot</em>. The distance of the bikers to the <em>parking lot</em> are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The <u>path</u> of travel of both bikers would form a triangle. Applying the <u>Pythagoras</u> theorem to the path of the <em>first</em> biker would give his <u>distance</u> from the starting point. While applying the <u>cosine</u> rule to the path of <em>second</em> rider would gives his <u>distance</u> to the starting point.

Thus,

a. <u>To determine the distance of the first biker from the parking lot.</u>

Let the required <em>distance </em>be represented by x. Applying the Pythagoras theorem, we have:

hyp^{2} = adj 1^{2} + adj 2^{2}

x^{2} = 8^{2} + 15^{2}

   = 64 + 225

   = 289

x = \sqrt{289}

  = 17

x = 17 km

Thus, the <u>first</u> biker is 17.0 km from the <em>starting</em> point.

b. <u>To determine the distance of the second biker from the parking lot.</u>

Let the required <em>distance</em> be represented by x. So that applying the cosine rule, we have:

c^{2} = a^{2} + b^{2} - 2ab Cos θ

x^{2} = 8^{2} + 15^{2} - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

x^{2} = 289 + 120

   = 409

x = \sqrt{409}

 = 20.2237

x = 20.22 km

Thus, the <u>second</u> biker is 20.22 km from the <em>starting</em> point.

Therefore, the second biker is <u>farther</u> from the <em>parking lot</em>.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

7 0
2 years ago
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