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maw [93]
3 years ago
11

Solve equations -8x=88

Mathematics
1 answer:
Alexxx [7]3 years ago
3 0
ANSWER:X=-11

Explanation

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I’m begging you please please ASAP ASAP please ASAP thank you please please ASAP
kozerog [31]

Answer:

The ratio is \frac{2}{3}.

Step-by-step explanation:

The ratio of the perimeters of Quad ABCD to Quad WXYZ = \frac{perimeter of ABCD}{perimeter of WXYZ}

But considering sides AB and WX,

representative factor for both figures = \frac{12}{8}

So that;

WX = 12

XY = 1.5 x 6 = 9

YZ = 1.5 x 7 = 10.5

WZ = 1.5 x 7 = 10.5

Thus,

perimeter of Quad ABCD = 6 + 7 + 7 + 8

                                           = 28

perimeter of Quad WXYZ = 9 + 10.5 + 10.5 + 12

                                           = 42

The ratio of the perimeters of Quad ABCD to Quad WXYZ = \frac{28}{42}

                                                         = \frac{2}{3}

6 0
3 years ago
100 points + brainiest
Scrat [10]

Answer:

  • 35 grams of 11.43% solution

Step-by-step explanation:

The end solution has same volume as initial volumes of mixture.

  • 10 + 25 = 35 g

The concentration of solution is calculated as below

  • 10*0.15 + 25*0.1 = 4 g
  • 4 / 35*100% = 11.43% (rounded)

6 0
3 years ago
Z divided by 3-2z + 4(z-8) when z = 18 <br><br> A. -122<br> B. 6<br> C. -66<br> D. 10
murzikaleks [220]

Everywhere you see z, replace the letter with 18.

z/[(3- 2z)] + 4(z - 8)

18/[(3 - 2(18))] + 4(18 - 8)

You finish.

3 0
3 years ago
a triangular flower bed needs a thin metal border all the way around it. The sides are 7 feet, 6 feet, and 9 feet long.
kotegsom [21]
Excuse my awful triangle drawing skills, haha..
So essentially you need to find the perimeter which is done by adding the lengths of the sides.. this gives you 22ft.
Then for part b you need to convert 22ft to yards which gives you 7.3 yards.
Since you can only buy a whole number of yards, you'll actually need 8 yards.
So if the boarder is $8.75 per yard, and you need 8 yards, how much would it cost?
Hope this was helpful.

7 0
3 years ago
Help me please. Find the measures of CAD and DAE
VladimirAG [237]

well, we know the "sum" of both angles is 90°, notice the rectangle in the corner, so we can say that the angles are simply complementary angles, thus

\left( \cfrac{3}{2}x+20 \right)+2x=90\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2\left( \cfrac{3}{2}x+20 + 2x \right)=2(90)} \\\\\\ 3x+40+4x=180\implies 7x+40=180\implies 7x=140\implies x=\cfrac{140}{7} \\\\\\ x = 20~\hfill \stackrel{\measuredangle CAD}{\cfrac{3}{2}20+20\implies 50}\qquad\qquad \stackrel{\measuredangle DAE}{2(20)\implies 40}

8 0
2 years ago
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