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Nikitich [7]
3 years ago
9

Stephen evaluated (6.34 times 10 Superscript negative 7 Baseline) (4.5 times 10 Superscript 3 Baseline). His work is shown below

. Which two statements describe the errors Stephen made? (6.34 times 10 Superscript negative 7 Baseline) (4.5 times 10 Superscript 3 Baseline). (6.34 times 4.5) (10 Superscript negative 7 Baseline times 10 Superscript 3 Baseline). 28.53 times 10 Superscript negative 4 Baseline. Negative 28.53 times 10 Superscript 4 Baseline. Negative 2.853 times 10 Superscript 3 Baseline.
Mathematics
2 answers:
Maksim231197 [3]3 years ago
7 0

Answer:

The step 4 and 5 describe the errors Stephen made.

Step-by-step explanation:

Given : Stephen evaluated (6.34\times 10^{-7})(4.5\times 10^3).  His work is shown below.

To find : Which two statements describe the errors Stephen made?

Solution :

Step 1 - (6.34\times 10^{-7})(4.5\times 10^3)

Step 2 - (6.34\times 4.5)(10^{-7}\times 10^3)

Step 3 - (28.53)(10^{-4})

Step 4 - 28.53\times 10^{4}

Error is the step as 4 sign is negative.

So correct step is 28.53\times 10^{-4}

Step 5 - 28.53\times 10^{3}

Error is the step as there is 4 in place of 3.

So correct step is 28.53\times 10^{-4}

The step 4 and 5 describe the errors Stephen made.

Zielflug [23.3K]3 years ago
4 0

Answer:

D and E

Step-by-step explanation:

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4 years ago
A woman making $3000 per month has her salary reduced by 20% because of sluggish sales. One year later, after a dramatic improve
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Answer:

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Step-by-step explanation:

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3 years ago
What percent is 52.52 million of 142 million
coldgirl [10]

Answer:

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Step-by-step explanation:

Given parameters:

Total number  = 142 million

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Unknown:

What percent is the number  =?

Solution

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an oatmeal recipe calls for 1 1/2 cups of oat and 2 1/2 cups of water. A If you have 3 cups of oats,how many cups of oats water
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\bf \stackrel{mixed}{1\frac{1}{2}}\implies \cfrac{1\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{3}{2}}~\hfill \stackrel{mixed}{2\frac{1}{2}}\implies \cfrac{2\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{5}{2}}\\\\[-0.35em]\rule{34em}{0.25pt}


A)


\bf \begin{array}{ccll}oats&water\\\cline{1-2}\frac{3}{2}&\frac{5}{2}\\[0.8em]3&x\end{array}\implies \cfrac{~~\frac{3}{2}~~}{3}=\cfrac{~~\frac{5}{2}~~}{x}\implies \cfrac{~~\frac{3}{2}~~}{\frac{3}{1}}=\cfrac{~~\frac{5}{2}~~}{\frac{x}{1}}\implies \cfrac{3}{6}=\cfrac{5}{2x}\\\\\\6x=30\implies x=\cfrac{30}{6}\implies \blacktriangleright x=5 \blacktriangleleft


B)


\bf \begin{array}{ccll}oats&water\\\cline{1-2}\frac{3}{2}&\frac{5}{2}\\[0.8em]2&x\end{array}\implies \cfrac{~~\frac{3}{2}~~}{2}=\cfrac{~~\frac{5}{2}~~}{x}\implies \cfrac{~~\frac{3}{2}~~}{\frac{2}{1}}=\cfrac{~~\frac{5}{2}~~}{\frac{x}{1}}\implies \cfrac{3}{4}=\cfrac{5}{2x}\\\\\\6x=20\implies x=\cfrac{20}{6}\implies x=\cfrac{10}{3}\implies \blacktriangleright x=3\frac{1}{3} \blacktriangleleft


C)


\bf \begin{array}{ccll}oats&water\\\cline{1-2}\frac{3}{2}&\frac{5}{2}\\[0.8em]5&x\end{array}\implies \cfrac{~~\frac{3}{2}~~}{5}=\cfrac{~~\frac{5}{2}~~}{x}\implies \cfrac{~~\frac{3}{2}~~}{\frac{5}{1}}=\cfrac{~~\frac{5}{2}~~}{\frac{x}{1}}\implies \cfrac{3}{10}=\cfrac{5}{2x}\\\\\\6x=50\implies x=\cfrac{50}{6}\implies x=\cfrac{25}{3}\implies \blacktriangleright x=8\frac{1}{3} \blacktriangleleft


D)


\bf \begin{array}{ccll}oats&water\\\cline{1-2}\frac{3}{2}&\frac{5}{2}\\[0.8em]x&3\end{array}\implies \cfrac{~~\frac{3}{2}~~}{x}=\cfrac{~~\frac{5}{2}~~}{3}\implies \cfrac{~~\frac{3}{2}~~}{\frac{x}{1}}=\cfrac{~~\frac{5}{2}~~}{\frac{3}{1}}\implies \cfrac{3}{2x}=\cfrac{5}{6}\\\\\\18=10x\implies \cfrac{18}{10}=x\implies \cfrac{9}{5}=x\implies \blacktriangleright 1\frac{4}{5}=x \blacktriangleleft

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Sergio [31]
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