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2 years ago

Mr. Hann is trying to decide how many new copies of a book to order for his students. Each book weighs 6ounces

Mathematics

1 answer:

Nina [5.8K]2 years ago

3 0

Answer:

I’m afraid I can’t help you. The question makes no sense because the question doesn’t explain how many students there are. It just gives the weight of the books which I assume is useless

Step-by-step explanation:

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Which solution to the equation (3/a+2)+2/a = 4a-4/a^2-4 is extraneous

MariettaO [177]

Answer:

$a=0\\a=2\\a=-2$

Step-by-step explanation:

We have $\frac{3}{a+2}+\frac{2}{a} =\frac{4a-4}{a^2-4}$

We are going to analyze both sides of the equation separately.

Part a: $\frac{3}{a+2}+\frac{2}{a}$

Applying common denominator:

$\frac{3}{a+2}+\frac{2}{a}=\frac{3a+2(a+2)}{a(a+2)}$

$\frac{3a+2(a+2)}{a(a+2)}=\frac{3a+2a+4}{a(a+2)}=\frac{5a+4}{a(a+2)}$

Part b:

$\frac{4a-4}{a^2-4}$

In the numerator we can apply common factor 4. And in the denominator we can apply difference of squares.

Remember: Difference of squares: $(a^2-b^2)=(a+b)(a-b)$

$\frac{4a-4}{a^2-4}=\frac{4(a-1)}{a^2-2^2}=\frac{4(a-1)}{(a+2)(a-2)}$

Then,

$\frac{3}{a+2}+\frac{2}{a} =\frac{4a-4}{a^2-4}\\\\\frac{5a+4}{a(a+2)}=\frac{4(a-1)}{(a+2)(a-2)}$

An extraneous solution is not a valid solution for a problem. We know that the denominator can't be zero.

The denominator of the first side of the equation is:

$a(a+2)$ and we have to see for which values of $a$ the denominator is zero:

$a(a+2)=0$ ⇒ $a=0$ and $a=-2$

The denominator of the second side of the equation is:

$(a+2)(a-2)$

And we have to see for which values of $a$ the expression is zero,

$(a+2)(a-2)=0$ ⇒ $a=-2$ and $a=2$

Then the extraneous solutions of the equation are:

$a=0\\a=2\\a=-2$

Because those are the values of $a$ that make the denominator zero.

7 0

2 years ago

Read 2 more answers

Find the area of quadrilateral ABCD. Round the area to the nearest whole number, if necessary.

andrew11 [14]

The area of the quadrilateral ABCD is 26 square units

<h3>How to find the area of quadrilateral ABCD?</h3>

The quadrilateral ABCD is a trapezoid, and it has the following parameters:

Parallel bases = BC and AD

Height = CE

The lengths of these sides can be calculated using

d = √[(x2 - x1)^2 +(y2 - y1)^2]

So, we have

BC = √[(0 - 4)^2 +(3 + 1)^2] = 4√2

AD = √[(-5 - 4)^2 +(4 + 5)^2] = 9√2

CE = √[(2 - 4)^2 +(-3 + 1)^2] = 2√2

The area of the quadrilateral ABCD is then calculated as

Area = 0.5 * (BC + AD) * CE

This gives

Area = 0.5 * (4√2 + 9√2) * 2√2

Evaluate

Area = 26

Hence, the area of the quadrilateral ABCD is 26 square units

Read more about areas at:

brainly.com/question/22972014

#SPJ1

8 0

2 years ago

If you deposit $5,000 into an account that pays 4.75% annual interest how much money will be in the account after 7 years if the

victus00 [196]

$6662.50

4.75% = $237.50
$237.50 x 7 = $1662.50

$5000 + $1662.50 = $6662.50

Answer = $6,662.50

4 0

2 years ago

One number is six times another number. Their difference is 35. What are the two numbers?

konstantin123 [22]

x - y = 35
x = 6y
Plug 6y in for x in the first equation.
6y - y = 35
5y = 35
Divide both sides by 5
y = 7
x = 6y
x = 6(7) = 42
42 and 7
Letter C
Since we had the answers we could have just tried the answers but you will not always have multiple choice so this is the method for solving.

4 0

3 years ago

Read 2 more answers

Name the vertex of angle 6.

amid [387]

Answer:

Step-by-step explanation:

∠ 6 is formed by the 2 lines that intersect at D

then the vertex of ∠ 6 is D

8 0

1 year ago